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Overunity Machines Forum



Formular to calculate energy per liter of HHO gas

Started by hartiberlin, August 21, 2007, 02:18:30 PM

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0 Members and 2 Guests are viewing this topic.

hartiberlin

Hi ?ystein,
many thanks for this correction.
Please can you post the WORD document or better in PDF format if you can ?

So you say that 1 liter  HHO ( H2 and O2 together) gas
has an energy value of 7744 Joules = 7744 Wattseconds.

So we only have to divide
7744 Wattseconds / 3600 seconds
to get:
2.15 Watthours of energy for 1 Liter of HHO gas.

So it is now the Faraday law barrier of 2.15 Watthours which you must be below to produce
1 Liter of HHO gas to be overunity.
Is this correct now ?

Many thanks.
Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum

kinggeorge



IS this over unity or just better than Fariday process.  I assume that if you hurn liter of HOH you ate saying it wll release equall amount of energy?

With ICE losses and alternator losses looks OU point and and HOH self powered points are very far apart.
George King

hartiberlin

Hi George,
100 % efficiency would only be 2.15 Watthours energy required for
1 Liter HHO gas for going from electric energy to HHO gas production.

Of course with added the low efficiency of the car motor of about 30 percent only
you still need to produce then even more HHO gas for this energy input.

But for the first time, just let us concentrate maybe to even
just half the gasoline consumption, so that would already be quite
an achievement, if you can run your car twice as long for the same
gasoline paid for cash..
Stefan Hartmann, Moderator of the overunity.com forum

xingu

I made some calculations too for another purpose but still usable in this situation:

Calculations on electrolysis of water (H2O)
Given
1 gram atom = atomic mass
1 gram mol   = molecular mass
Water = H2O, so 2 atoms H and 1 atom O
Question: how is the distribution of mass in 1 molecule of water (H2O) in % H and O.
Calculation
Atomic mass H= 1
Atomic mass O=16
So the Molecular mass H2O=1+1+16=18
Total mass of H in water=2/18x1%=11,11%
Total mass of O in water=16/18x1%=88,89%

Given
1 liter of water has a mass of 1000 gr and equals 1000 cm?
1 liter of molecular H has a mass of 0,09 gr, 1 liter of molecular O has a mass of 1,47 gr
Question: how many liters of H2 and O2 are contained in 1 liter of H2O
Calculation
For H2: Total mass of H in H2O 11,11% (See question above)
so 11,11%x1000 gr=111,1 gr of H
111,1/0,09x1 liter=1.234,44 liter H
For O2: Total mass of O in H2O 88,89% (See question above)
    So 88,89%x1000 gr= 888,90 gr of H
    888,90/1,47x 1 liter= 604,69 liter O

So in your case from 1 liter of water you get app. 1.800 liters of HHO gas.

oystla

Yes, Stefan

of course, you are right, So your original proposal was not far off anyhow.

But since the experimenters collect their gas generally through bubblers and measure volume, I would say my formula is more straight forward to use for calculating efficiency.

Also, this takes care of/assumes any water saturation, and that gas collected holds approximately 20 degC, 1 atm..

One thing that the experimenters should be aware off is that pressure may build up in the bubblers of some set ups, and will distort the mauserment, but not much I think...

Another item; I get warnings from my security software of "spyware" when I open your website, and it states "ads.adbrite.com/adserver/....."

Anything to warry about ?


regards
?ystein