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Quadrant Machine

Started by bunion, September 26, 2007, 07:38:33 PM

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0 Members and 2 Guests are viewing this topic.

bunion

Hi, ive come up with a few ideas on the site below and it would be great to get some feedback on them. I have shown one to a family freind with a respectable background in physics and he says it will not work even if you discount friction from the machine.

http://www.philiplarner.pwp.blueyonder.co.uk

The idea is to, increase work done by a piston in a hydraulic system but he says although the piston will move a greater distance the force with which it is done will decrease.

bunion


argona369

Hi bunion,

It?s nice to see your 3d thinking but it won?t work.
In its simplest form imagine a 10x10 square piston
On one end of a tube and a 5x5 square piston on the other end
Whenever the 10x10 piston moved one unit , the 5x5 would move 4 units.
But the 5x5 piston has ? of the surface facing the hydraulic pressure, and hence ? of the
power. It just balances out.

Free energy is not an easy thing to do! So far, there is no such device invented. that
has proven and reproducible over-unity performance with proper measuring.
Lots of claims, but nothing a university would endorse (yet).

Hissy is just venting his frustration with Ash on you.

Ps,
maybe try looking at the Testatika.
The only electrostatic device purported to produce
free energy.
(Correa's  Abnormal Glow Discharge is another but
is plasma based)
Even if the testatika turns out to be a fake, electrostatics (and plasma)
is for me at least something ?different? in the free energy research field.
And very little explored.

bunion

Thanks for the feedback argona369. Sorry if im missing your point here but, isn't that just normal hydraulics? I realise everything balances out in your example. My idea is trying to manipulate the fluid required to push a piston using a quadrant shape, without changing the surface area of the pistons. They can be the same size even.

argona369

Hi,
I see what your trying to do here I think.
http://www.philiplarner.pwp.blueyonder.co.uk/idea5.html
But the useful force on the piston is just the same as if the piston was flat.
(*the cross section in the direction of movement*).
Maybe imagine two pivotable rocket thrusters.
If they are set inline to the rocket , you get full thrust.
If they are 90 degree ?s and opposite set you get zero thrust.
hope that helps,

Quote from: bunion on September 30, 2007, 04:51:59 AM
Thanks for the feedback argona369. Sorry if im missing your point here but, isn't that just normal hydraulics? I realise everything balances out in your example. My idea is trying to manipulate the fluid required to push a piston using a quadrant shape, without changing the surface area of the pistons. They can be the same size even.