Possible Overunity

[hartiberlin]

Hi Singer,
buy a 1 Ohm
10 Ohm,
100Ohm and
1000 Ohm
all 10Watt type resistors
and use this instead of the neon
bulb as the load.

Then connect each resistor once as the load.
Then measure the voltage across the different resistors
and post each DC voltage at each single resistor.

( Of course put only one resistor of this list to the output and then measure each one by one)

[singerxyz]

Tested current with 10 ohm 10 watt resistor and got .13 amps with slightly lower voltage.
(Batteries are close to dead- need to buy more)
I'll pick up the 100 and 1000 ohm resistors and batteries tomorrow and post results.

mramos-
the meter was shown up to .29 amps. Is that not close to .33? Mockery is not helpful except to reveal character. And as far as what "was not seen" was obviously me taking the leads off the neon bulb and putting them on the volt meter.

[linda933]

Tested current with 10 ohm 10 watt resistor and got .13 amps with slightly lower voltage.
(Batteries are close to dead- need to buy more)
I'll pick up the 100 and 1000 ohm resistors and batteries tomorrow and post results.

mramos-
the meter was shown up to .29 amps. Is that not close to .33? Mockery is not helpful except to reveal character. And as far as what "was not seen" was obviously me taking the leads off the neon bulb and putting them on the volt meter.

Hi again, Singer,

One thing you said struck me and that was that you were measuring the current "open circuit".  You know, that when you set your meter to any of its current scales and plug into the appropriate jacks, the meter acts as a near short circuit internally.  DMMs are all actually voltmeters.  To get a current reading, they just throw a fat low value resistor across the jacks inside and then measure the voltage drop across it. 

Per Ohms law, if the internal shunt is 0.1 ohm and the current readout says 10A, then there will be a voltage of 1V between the meter jacks.  Just remember that in Voltmeter mode, your meter will have a very high resistance (ideally infinite) and in Ammeter mode it will look like a very low resistance (dead short ideal).  So when you do your resistor tests, measure voltage across (parallel) the resistor and measure current by inserting the meter in series with the test load resistor, not across it.

Probably you already knew all that, but I just wanted to clarify in case you weren't sure.  When you put a current tester directly across the output of your circuit it's a virtual short circuit because of the internal shunt.  I can't count how many times I've blown up the fuse in my meter by forgetting to rearrange the test leads into the right jacks and sticking the meter (still set for a current test) across some beefy power source. 

Anyway...happy testing and don't be discouraged if overunity operation eludes you for a while.  It's managed to hide from the mainstream of practical commercial technology for a very long time!

Linda

[singerxyz]

Linda,
Thank you for the helpful and encouraging words. I didn't know anything about resistance testing, and this helps a great deal. when you say measure 'across'' I assume you mean put + on one end of resistor and - on other and voltmeter same? And series would be + on one end of resistor and voltmeter + on the other side with - running straight through to meter?
Sorry to bother you with something so elementary as this, again I'm a little green.

[singerxyz]

No worries mramos, thanks for writing back.

Anybody know the best way to send current back to run the timer once the unit is started? it needs to replace 18V from two 9V batteries.