Self Running Micro TPU, with closed loop.

[Bruce_TPU]

@ Plengo

Thank you for the drawing.  One question.  Which wires are the 23awg and which are the 18awg?  Also, the gate to the Mosfet is not connected to anything?

I know that the LED's are rated at 20 ma but if you could give an exact amperage and voltage reading of an actual LED that would be helpful.  Working with the 1.26 watts as stated by the battery, that would be helpful.

@ All
After draining my newest battery for 18 hours, the voltage has recovered, by itself from .01 volts to 6.48 6.95 and still climbing.  These battery are very, very, very difficult to drain.  I am not trying to be a skeptic, just reporting the facts, so far.  That is why I want to do the Ohms law calculation on Fausto's circuit and see how long it would have to run to surpass stated wattage of battery.  This would be based on actual voltage, amperage measurements of the LED's.


Holiday Cheers,
Bruce

EDIT:
After draining my newest battery for 18 hours, the voltage has recovered, by itself from .01 volts to 6.48 6.95 and still climbing.

Voltage of battery connected to circuit has gone up to 7.17 volts.

EDIT #2:
I think that I have hit on a good plan for a test. 

Step 1:  When the drained battery that has self recovered itself to 7.17 volts, I will connect it to my mini motor and time how long it runs (if at all, my guess is very little amperage)  I will post that. 

Step 2:  I will then remove present battery from my oscillator and put in the drained battery.  When it's voltage, attached to the oscillator once again reads 7.17 volts I will remove it and again connect it to my mini motor and time how long it runs.  I will post that.  If it runs longer after being attached to the circuit then it did by simply being left alone to recover, I think will be indisputable proof that there is indeed something to this, and that it is not just the super battery doing it's thing.

[plengo]

@btentzer
man I hate to be sick. Having fever.

The D2 voltage is 1.64v and D1 is 2.48v. Current going through all of the D1s is .2ma (point two milliamps) (it is between the Source of the mosfet and the first D1). Voltage cross battery now is 8.18v. Very steady current. I assume the current was always like that or higher.

Note: This circuit has been running NOT in the faraday's cage. I am going to add some more LEDs and if voltage still does not drop than I will hide it under a cage and leave it there for a good week. Cross the fingers.

I started another version, again  , this time I made a bifilar coil using 200 turns of 26 awg and 30 (http://www.radioshack.com/product/index.jsp?productId=2036277&cp=&sr=1&origkw=magnet+wires&kw=magnet+wires&parentPage=search).  Same circuit but much smaller and compact coil. 27 LEDs (D1) plus one 3mm LED (D2) (referencing the drawing again). Lets see if this will work.

Fausto.

[Bruce_TPU]

@ Plengo

I hope that you get to feeling better!   

Based on my math, and the figures you have provided, I come up with a run time of 126 hours based on a fully charged metal hydride battery.  If someone else can do the math and see if you come up with the same number.  I am basing it on 1.26 watt capacity of these batteries as stated on the package.

Holiday Cheers,
Bruce

[Groundloop]

[EDIT] Deleted.

[plengo]

@Groundloop
so if you right, does it means that If my circuit run for more than a full week it passed the capacity of the batery? This is a 150mah battery. If I am consuming .2 milliamps I would say it will take 150/.02 = 750 hours to run, so I need one full month, no? (I am horrible with mathematics   ).

Fausto.