Muller Dynamo

[Rawbush]

A couple of questions
if you find the resonance of an lc circuit then start to pull energy from that circuit wont it change the resonance. I think you definitely need a scope to tune the coils at load.
What bother's me is how to control rotor speed (frequency).

In order to control motoring speed, I put a potentiometer in series with the power. This allows for some adjustment but not complete  control. I think we are all finding just how tuned Romeros motor really was. Also I wound up a 5 strand coil yesterday and will do measurements ( L,C,ohms) tonight and post, There are over 100 ways to hook up 5 wires so if anybody has ideas to test please post. Well off to work for the day.
Peace
rawbush

[mondrasek]

I believe the RomeroUK Muller Generator is acting as a conventional generator with a delayed (or retarded) Lenz drag due to the presence of the FWBR and dump capacitor.  These results are from experiments done with a real setup.  Please note the wave form I drew below.  Sorry it is not a picture of the o-scope, but I am not at home now and only figured out what it means early this morning while getting ready for work.  The wave form is what I witnessed when measuring the voltage out of a coil pair and across a .1 Ohm current shunt resistor (for a current wave form by measuring voltage drop).  This is the wave form only after a load (14.4V 100ma lamp) is attached to the output dump cap.  Before the load is attached there is NO current form at all.  The coil pair is matched by wrapping the same length of wire(s) on each and then fine tuned to the same induction by inserting a ferrite core until readings are identical (1.2 mH) on an induction meter.  I have one coil pair wound single filer and a second pair wound as Tesla coil bi-filer (end of first wire attached to beginning of second).  The output wave form of both types of coils was identical in every respect.  Their initial output was matched by adjusting the distance of upper and lower coils to the rotor while watching the output of each individual coil, two at a time.  Kinda hard to do since the different magnets cause slightly different outputs which make the wave forms a bit jumpy, but I did the best I could.

I was looking for a phase shift between the current and voltage forms as @bolt has been indicating.  I believe that is one way to achieve the Lenz defeating nature of a system like this and therefore achieve OU.  But I do not think that is what RomeroUK has done here.  I was able to witness absolutely no phase shift on either coil pair at any RPM from 0 to ~2280.  The rotor is spun by a small motor (VCR head spindle, bearings, and motor) and driven by a variable regulator off of a 15V laptop power brick.  Rotor achieves max RPM at around 14V (max regulator output) and 290ma with no load.

Here is what I believe is happening:  With no load there is no current draw from the coils.  When the load is applied there is a current draw.  But before current can flow, the coils need to “see” the load.  Before they can see the load, they must generate enough voltage to overcome two things.  First, they must overcome the voltage drop of the FWBR.  Then they must also overcome the voltage level that is already in the dump cap.  So current will not flow until the coil output voltage level rises to a value greater than the diode voltage drop + voltage in the dump cap.  During the time that the coil output voltage is below this value, we have no Lenz.  Once the coil voltage exceeds this voltage, current does flow to the dump cap, and Lenz appears.

This system is defeating Lenz for part of each coil voltage cycle, at the beginning of each magnet approach, and at the end of each magnet retreat.  The system has normal Lenz during the middle of each magnet pass.  So the rotor does slow down a bit when the load is attached if the current draw is greater than what is passed to the dump cap by all the coils.  But if the load is less than what each coil is outputting to maintain the max dump cap voltage, you will not see much RPM drop if at all.

Since the middle Lenz portion of each magnet pass is pushing real current, you will see RPM drop as you tune to a load.  This would account for the relatively high input current to RomeroUK’s system that has been mentioned.

Thanks,

M.

[darkwanderer]

@mondrasek

Are you sure that your current wave form is like that?

[xenomorphlabs]

@mondrasek

Are you sure that your current wave form is like that?

Can't be really, or his current and voltage would have different frequencies.
But that should not distract from the point he was trying to make.

[mondrasek]

@darkwanderer, actually I was just thinking that myself and I believe I drew that wrong.  I have attached a revision that I believe is correct now.  But I will double check tonight.

@xenomorphlabs, frequency is the same.  Only the current trace is not a continuous sine wave.  It is blips of sine wave separated by flats of zero current when the coil voltage has not yet exceeded that of the FWBR drop + dump cap voltage yet.