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Overunity Machines Forum



Muller Dynamo

Started by Schpankme, December 31, 2007, 10:48:41 PM

Previous topic - Next topic

0 Members and 46 Guests are viewing this topic.

nul-points

Quote from: k4zep on May 16, 2011, 08:26:49 AM
Just looking at details, I noticed at 2:54 into the FIRST video right after he had turned on the load, Output meters read about 12 VDC and 2A.

But has any one noticed the input voltage.  Just a few seconds before it was 12.57 VDC @ .92 Amps.  When he turned on the output lamp,
the voltage was 12.29 and dropping fast, input current had not changed but battery was showing as if another load was on the battery!  As I recall, RomeroUK was asked this same question by another person and there was no answer.

Ben K4ZEP.

hi Ben

Romero did answer, iirc he explained that in the first video he had his o/p looped back to his i/p via a diode

when off-load the diode was lifting the i/p volts

when he connected an extra load the feedback was reduced and the i/p volts fell a little

seemed reasonable to me

hth
np

[EDIT: oops, sorry for the reply clash, lumen!]

http://docsfreelunch.blogspot.com

"To do is to be" ---  Descartes;
"To be is to do"  ---  Jean Paul Sarte;
"Do be do be do" ---  F. Sinatra

khabe

Quote from: yssuraxu_697 on May 16, 2011, 08:35:47 AM
Dont worry. Once you run it thru sim and see the flux map you would not want to use such spools. It has been talked about already.

Really? But if you do not have  "such spools", then flux from moving(!) magnets acts direct to coil wire, in coil turns will be induced opposite currents, half of coil turns produce negative, opposite half produces opposite emf,  there is conflict between Lorentz force and Faraday's law.
"Such spool", you said, this is the best 8)
cheers,
khabe

k4zep

Quote from: lumen on May 16, 2011, 09:03:44 AM
Romero said there was a diode from the dynamo to keep the battery charged, adding the load reduced the output voltage enough where the battery was no longer charging so the battery voltage dropped.
Same voltage drop you would see by simply removing a battery charger from the battery.

Is this from a personal conversation with him or a email or message number, I didn't read it, seemed to be silent on that question.
I understand the rational of the answer and what is going on.  Somewhere around 12VDC, it would have possibly stabilized with the 2.9A load assuming rotor speed stayed the same or close.


Thanks
Ben K4ZEP

k4zep

Quote from: nul-points on May 16, 2011, 09:04:49 AM
hi Ben

Romero did answer, iirc he explained that in the first video he had his o/p looped back to his i/p via a diode

when off-load the diode was lifting the i/p volts

when he connected an extra load the feedback was reduced and the i/p volts fell a little

seemed reasonable to me

hth
np

[EDIT: oops, sorry for the reply clash, lumen!]

http://docsfreelunch.blogspot.com

Thanks for both the answers, clear now!

Ben K4ZEP

baroutologos

Quote
Just looking at details, I noticed at 2:54 into the FIRST video right after he had turned on the load, Output meters read about 12 VDC and 2A.

But has any one noticed the input voltage.  Just a few seconds before it was 12.57 VDC @ .92 Amps.  When he turned on the output lamp,
the voltage was 12.29 and dropping fast, input current had not changed but battery was showing as if another load was on the battery!  As I recall, RomeroUK was asked this same question by another person and there was no answer.

I in no way want this to be negative question, just something I noticed, in light of the self running, maybe does not need to be answered.

Ben K4ZEP.


Hello Ben,

i know Romero more than anyone here i guess so i feel that i somehow should answer that question.
I have replicated more than 3 or 4 OU promising devices conceived by Romero, being all of them short of OU. Afterwards, indeed, he admitted his inspirations were not OU but close to it. (not selfrunning or anything promised or claimed to had achieved by them)

....
This observation, you made i made during posting his 1st video. i told him so, and he somehow got angry with me. (I am a sceptic still being an experimenter).
Then when he assembled his self runner it was specially made for me.
They were not few the times that i had strong disagreement with  Romero regarding his observations and measuring techniques since he refrained far from any contemporary scientific approach that despises a bit. He is guided from an inner inspiration and an untiring mood and for new experiments.

This is very well demonstrated in his forum that we had this post-exchange. (i have posted back ben forum's last 2 pages in zip. download and see yourself)
In my accusations, :)  Romero replied that his motor had an energy re-cycle procedure (flyback harvest i suppose) that is not depicted in any diagram so far put forth. This flyback energy collection goes to common power rails as the FWBRs after the pick up coils.

So, for a given battery (that must be partially depleted) when idle voltage is 12.65, when running with flyback on, (since motor underunity and pickup coils should output less than 12,3 volts) then voltage declines below 12.45 (as per video). When load on, (on the common power rails) voltage should decline to a level that is suitably supported by the battery and pickup coils.
In anyway, this video is totally inconclusive of the OU potential of this device.

....
Personally, i am not motivated to make a replica because of a self-running video, rather than because i know Romero and respect him.
My advice is try to replicate the device as closely as possible, suppressing your urge to "grab a concept" and improvise.

I will do this way, myself.