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Overunity Machines Forum



Muller Dynamo

Started by Schpankme, December 31, 2007, 10:48:41 PM

Previous topic - Next topic

0 Members and 38 Guests are viewing this topic.

k4zep

Hi Romero,

Just remember the strongest tree on a mountaintop is the one buffeted by the strongest winds.  My best creative work in life always occurred when I was pissed off and said "I'll show them/her/it and myself".  I might not make it work but will give it a hell of a try over time.  Sometimes I am so dense I just can't see my nose in front of me, but eventually I understand.  At some time during the process, perhaps I will "see the light" of understanding as to what is really going on here.  I'm sure it is subtle but right in plain sight,  It obviously is not just a plain motor/generator/converter interface..........I just wish I had a clear understanding of what to look for when I "tune" the device.  I understand the speed, max output, distance, bias magnets, core diameter/coil turns, etc. but the magic to look for to tune for maximum effect, what the heck is it, what am I looking for?  Again, just me thinking out loud.  Glad you are hanging around.  Take care.  I"m a old retired Electronic Tec,. have a daughter who is a IT specialists, etc. and I actually do this for fun.

Respectfully
Ben K4ZEP


ZeroFossilFuel

Quote from: romerouk on May 16, 2011, 03:37:38 PM
Hi all,

I have been looking arround here and folowing most of the attempts to replicate the device I have presented and all I can see is that most of you are going in the wrong direction.
In my previous posts I have really told you all but beople can see only what they are familiar with.
You all see magnets rotating in front of the coils... , at 1240rpm we get too low voltage...maybe at 1034 we get better... that is just an ordinary alternator/dynamo but this one was a bit more than that.
If you are considering to build a very efficient dynamo then you are on the right track if you want to investigate more then use your brains.
Here are many people very clever but I think that is their handicap (not all but some)
'My friend' Baroutologos (who started all my current problems) was always in conflict with me regarding my simple way to approach every device I started, but he was going arround in circles because the law of physics are not permiting,...  many...
There is a lot more to be discovered and maybe change or add to the existing laws of physics.
For all who are not really seeing a bit more in here is no point to spend your time and money, wait until those few will manage to understand and you will have more details.
I wont be here to guide anyone as I am considered a master of 'magic (hoax) and maybe I am.
I am already in a lot of .... I don't need anymore.



Best regards to all,

RomeroUK

PS: don't wast time with that LED, it is powered back from the driving coils via the recovery diodes too simple to be seen and  understood...

Romero, I hope to be taking some pressure off you soon. Only changes to my model are 9.5mm ferrite dia and Schottky diodes in place of the "enhanced bridges" for half the voltage drop loss.

So I guess this means you won't be joining us for the Smart Scarecrow show this Thursday?  :-\
My public PGP key. Please help support my work. Donate by PayPal

hartiberlin

Quote from: lumen on May 16, 2011, 05:04:06 PM



Tinu,
What is it you just don't get!
Once the power to the coil drivers are switched off, the output of the DC/DC converter goes to 12v or higher because of the recovery diode.
With no load on the DC/DC converter but with 12v still provided from the large 47,000uf capacitor the only draw is the LED.
How long could a 47,000uf capacitor keep an LED lit?
D.A just give it up!

Well,
I must admit, that Tinu is IMHO right in his critique.

Have another look at the circuit drawing at:

http://www.overunity.com/index.php?topic=3842.msg286835#msg286835

There you can see, that the switch RomeroUK is switching
off only cuts off the voltage from the cap and the input of the DC2DC
converter.
Nothing else is switched off...
So how can the LED really stay lit for 43 seconds is a real question
when we don´t know, where this additional recovery diode is ?

For the LED to be lit it should be D2, but then the switch
does not work as the recovery diode would just short it out...
If it is D1, then DC2DC converter would be obsolete or redundant
and the 15 Volts DC would directly go to the driver input and we would
have a runaway...!

So the question is really important, where is this recovery diode and
what does it exactly do !

Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum

tinu

Quote from: lumen on May 16, 2011, 05:04:06 PM



Tinu,
What is it you just don't get!
Once the power to the coil drivers are switched off, the output of the DC/DC converter goes to 12v or higher because of the recovery diode.
With no load on the DC/DC converter but with 12v still provided from the large 47,000uf capacitor the only draw is the LED.
How long could a 47,000uf capacitor keep an LED lit?
D.A just give it up!


The recovery diodeS (two of them) are there and working at all times, not just when you think they are needed to raise one voltage or another.
The power to the coil drivers is NOT switched off. NEVER.
I think it’s either my English or you don’t get it.

@Tudi,
I’ve got that 50% part for the last many years. I still enjoy it when there is something solid to investigate and build. So far, I expect Romero stands up like a man and shows us how wrong I am and then he shows you the real ‘missing secret’ or else you will build a mere dynamo like he said you will…

@Stefan,
Many, many thanks. I now go silent until something changes.

TEKTRON

Quote from: hartiberlin on May 16, 2011, 03:33:47 PM
Hmm,
the pre-resistor for the LED can not be 100 Ohms.
This is a much too low value.
I just calculated it,
at 15 Volts there would be already flowing 150 Milliamps which would
be more than 2 Watts at this small resistor and it would smoke
and also the LED would smoke at this large current...

So could this be 1000 or 10K Ohm ?
What does 102 or 1D2 mean ?

102= 10 + 00= 1000 or 1k
101= 10 + 0  = 100
103= 10 + 000=10000 or 10 k