Muller Dynamo

[e2matrix]

@wattsup,  thanks for your contribution in trying to figure out some of this.  A couple questions.  Are you building this or do you have it built?  If not then I have to ask if theory always works out to be valid in a real world build?  We know it does not.  So I am only asking why you are certain this will make it run better as it does not seem Romero mentioned this and it seems he would have been aware of this.  And since you seem to have a handle on the theory why not provide a circuit to support it?  Even a block diagram circuit might help and others can fill in the details.  Or maybe just a logic-flow diagram.  Do we need a flip-flop circuit?  I don't think Romero was using that.  Not trying to be critical here just trying to get more pieces of the puzzle.  Thanks again for your input. 

[i_ron]

Hi All,

I can see a lot of bickering and not a lot of progress happening on this thread.


All the best

  Chris

Chris, excellent video, well filmed and nicely narrated.

What you call bickering is, I'm afraid, necessary as various details are worked out. Facts that are not supported by evidence are of no value.

The series capacitor was being discussed... so to clarify this further I have put together a little test... draw your own conclusions, or replicate yourself, if you wish.
-----------------------------------------------------------

A test is worth a thousand words, to paraphrase an old saying.

What does a series capacitor before the FWB do?

Parts: Hammond transformer, FWB, 6800 mfd, 63 volt filter cap, 20 ohm load resistor and various oil caps from 6 to 56 mfd

Meter: Clamp on, on 120 volt supply, ammeter from FBR plus to load, volt meter over load.

Base line:  .08 A to transformer, no load

Top circuit: no caps,  ip, .27A;  21.7V @ 1.08A;  ip = 32.4 watts; op = 23 watts

Mid circuit:

6mfd, ip .07A; 1.2 V @ .05A; ip = 8,4watts; op = .06 watts

45 mfd, ip .04 A; 8.4 V @ .42 A; ip = 4.8watts; op = 3.5 watts

96 mfd, ip .1 A; 14.7 V @ ,74 A; ip = 12 watts; op = 10.8 watts

Bottom circuit:

48 + 56 mfd; ip .04A; 4.8 V @ .24 A; ip = 4.8 watts; op = .192 watts

96 + 98 mfd; ip .04A; 8.5V @ .42 A; ip = 4.8 watts; op = 3.57 watts

Conclusion:

With a single capacitor of low value the output is minimal. (.06 W!)
Of interest is that with limited output, the input draw is below that of no load condition, only exceeding the base reading when the output approaches half the conventional reading.

On the double capacitor setup 100mfd or more is required to get any usable output but in each case shown, the input amps remained at one half the no load reading.

Rgds, Ron

[Arthurs]

Take OUT  C1 and C2 and leave C3 as the adjustor.  Put scope leads across C3 and the other channel across R1.

Short the DC side of the bridge out and work only on the AC side for now. You will know when you are in tune because the volts and the amps will peak very high compared to other values.  If the phase will not go out of phase try  reversing the coils pair.  Try winding more coils using say 500 turns of 24 awg  NOT litz wire and keep doing stuff like this until you see a "HOLY CRAP"!!! moment on your scope shots. You need to see amazing high VARS before you open the short into the dump cap. Try winding bifialr coils two strands of 24 AWG or something pretty thin wire then cross the ends just like a joule thief.  You need everything to go out of phase BETWEEN the coils and WITHIN the coils themselves to stop current flowing because  current = lugging.

Only when you see amazing  VARS with no lugging open the DC pathway.

Hi bolt:

    Thank you very much reply guidance.
    Because my English is not good, Can not fully understand what you mean, Can only think about. Very anxious!
    So: You can draw a diagram to help me understand?

    According to my current understanding, the following circuit diagram is like this, correct?

    My next experiment steps:
    The rotor speed to maintain the premise in 1200rpm, 20 ohm load resistance.
    Generation coil 500 turns from the start, Adjusted every 20 turns to reduce the test.
   
    Since the adjustment of Generation coil, R1 and C3 is also necessary to re-adjust it? If you need to adjust, Their values ​​were roughly what should be in the range?

Thanks again

Welcome to all the above problem to discuss.

[k4zep]

Take OUT  C1 and C2 and leave C3 as the adjustor.  Put scope leads across C3 and the other channel across R1.

Short the DC side of the bridge out and work only on the AC side for now. You will know when you are in tune because the volts and the amps will peak very high compared to other values.  If the phase will not go out of phase try  reversing the coils pair.  Try winding more coils using say 500 turns of 24 awg  NOT litz wire and keep doing stuff like this until you see a "HOLY CRAP"!!! moment on your scope shots. You need to see amazing high VARS before you open the short into the dump cap. Try winding bifialr coils two strands of 24 AWG or something pretty thin wire then cross the ends just like a joule thief.  You need everything to go out of phase BETWEEN the coils and WITHIN the coils themselves to stop current flowing because  current = lugging.

Only when you see amazing  VARS with no lugging open the DC pathway.

Hi Bolt,

Thanks, will try it this afternoon (after nap, Hey, Edison loved his afternoon naps too!", , might have to wind some new coils.  Will first drive the inductance with a sig generator to get C into ballpark then fire up the motor and see if it does peak and unload at resonance.
There should be a hell of a sweet spot if/when it does. 

Respectfully
Ben K4ZEP

[Arthurs]

Hi Arthurs,

Nice work.  Will test it on my unit later today!  Thank you.

Respectfully
Ben K4ZEP

Hi K4ZEP:
   My experiments did not progress.
   I look forward to your good progress, I hope you have a break!
 
   Cheers