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Overunity Machines Forum



Muller Dynamo

Started by Schpankme, December 31, 2007, 10:48:41 PM

Previous topic - Next topic

0 Members and 6 Guests are viewing this topic.

darkwanderer

According to Romero circuit the voltage and feed current for the capacitor should be like in the image below....
http://imageshack.us/photo/my-images/16/romerodemo.jpg/

The current is shown as yellow wave form and the voltage is green. So when we look these wave forms we see that romero's dynamo draw current from the coils only when the voltage drop is enough at the capacitor.(like mondrasek said). Ä°f this theory is right then we should look the vector's (pull, push, attraction etc....) of the dynamo..

http://imageshack.us/photo/my-images/585/vectors.jpg/

As we see that if the push force created by the drive coils is enough powerful as the force created by the collector coil then we have no problem at all, the rotor will turn without any problem. I think the proof of using top and bottom coils is for balancing these forces. Because if we got only 1 side push we can have problems with the dynamo while turning because we don't have counter force on the opposite direction of the rotor(we don't have same count of magnet and coil)...


Ä° think if we got these thoughts together and romero told(if i remember correctly) that the capacitor and the distance etc... was important. The main idea is the capacitor is working like a switch when the magnet is on the right position, it open the FWBR and let the current flow.When the current flow the lenz force created is not so powerful to beat the force created by the drive coils.

I'm thinking about this idea for several days but there are problems about it:

1-)When romero turn the switch on and current start to flow to the capacitor. With my idea it has to slow down the rotor a little bit until the capacitor fill. When i watch the video i couldn't see that.(maybe you can i'm not a professional with this video stuff)

2-)Secondly with this idea you cannot short the output of the circuit. Ä°f the lenz force beat the drive coils force It'll slow down the rotor.

mondrasek

Quote from: darkwanderer on July 07, 2011, 12:21:41 PM
1-)When romero turn the switch on and current start to flow to the capacitor. With my idea it has to slow down the rotor a little bit until the capacitor fill. When i watch the video i couldn't see that.(maybe you can i'm not a professional with this video stuff)
Capacitor was pre-charged.  Mine does slow down while charging the cap after I short it out.  But if I start with it charged and no load, the rotor does not slow down until the load is applied.

Quote from: darkwanderer on July 07, 2011, 12:21:41 PM
2-)Secondly with this idea you cannot short the output of the circuit. Ä°f the lenz force beat the drive coils force It'll slow down the rotor.
I believe direct coil shorting was not shown in the video.  RomeroUK just pointed us to that effect as a way to start experimenting and eventually it would lead to this Muller design.  Because this is using a type of coil shorting, right?  The timing is controlled by the FWBR and dump cap voltage.  Very clever, really.

darkwanderer

Quote from: mondrasek on July 07, 2011, 12:32:55 PM
Capacitor was pre-charged.  Mine does slow down while charging the cap after I short it out.  But if I start with it charged and no load, the rotor does not slow down until the load is applied.


I believe direct coil shorting was not shown in the video.  RomeroUK just pointed us to that effect as a way to start experimenting and eventually it would lead to this Muller design.  Because this is using a type of coil shorting, right?  The timing is controlled by the FWBR and dump cap voltage.  Very clever, really.

Ä°f my idea is right he mustn't short the output the rotor will slow down. He also said that to use load when we try to replicate.Good idea using capacitor as a timing element for the current control. So to prove this idea we need the current wave form of romero's muller dynamo. Unfortunately we don't have that opportunity now... :-\

mondrasek

Well I am continuing on with my build.  Having a selfrunner will prove it good enough for me.  The next step will be to decrease the coil to rotor distance until I have an output that provides the 15 V input my drive motor regulator needs.  At that point I can check the current output to see if I have enough power from the coils to move forward with adding all 9 pairs.  If I don't have the power I will have to re-design the coils.  They are ~200 wraps of 24 AWG now so my voltage is low and I may not get there without more wraps and/or smaller wire.

M.

gyulasun

Quote from: darkwanderer on July 07, 2011, 12:21:41 PM
According to Romero circuit the voltage and feed current for the capacitor should be like in the image below....


The current is shown as yellow wave form and the voltage is green. So when we look these wave forms we see that romero's dynamo draw current from the coils only when the voltage drop is enough at the capacitor.(like mondrasek said). Ä°f this theory is right then we should look the vector's (pull, push, attraction etc....) of the dynamo..



....

Hi darkwanderer,

When I click on your links to the pictures my Firefox browser reports an error that it cannot find that url and strangely it points to this: http://www.yukle.tc/    while your link starts with http://img385.yukle.tc/images or img389.yukle.tc/images etc  so what is wrong?  Maybe at my side?

Hi Mike,

I think you do a good job and wish you steadily continue...  Whenever you change coils, gaps etc, always sweep the RPM ranges your controller insures to see the loaded output behavior, for load values try to use similar resistor values what may come from your 15V DC input voltage and drive motor current of 200-400mA establishes.  This may involve having any resistors between 15V/0.4A=37 Ohm to 15V/0.2A=75 Ohm,  wattage could be 5 or 6W for continuos or just 2W for intermittent tests.

Gyula