Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Muller Dynamo

Started by Schpankme, December 31, 2007, 10:48:41 PM

Previous topic - Next topic

0 Members and 318 Guests are viewing this topic.

RAD-HHO

Quote from: DeepCut on December 08, 2011, 02:51:02 PM
Oops !

Yes i meant R, as i said originally :

"Power=Voltage squared / resistance,"

So how do i measure both simultaneoulsy ?

I know there is current there because i can light CFL's.

You don't! You measure Voltage and current. You have to have both to have power.
The cfl is high frequency, and as you stated before, you need a scope for that.
Rick

DeepCut

Quote from: RAD-HHO on December 08, 2011, 02:54:53 PM
You don't! You measure Voltage and current. You have to have both to have power.
The cfl is high frequency, and as you stated before, you need a scope for that.
Rick

I don't what, measure them both simultaneously or i don't have current ?

I know i have current because i can also light incandescent bulbs and drive small motors.

How do you measure both of them simultaneously when you're doing your HHO stuff ?


Cheers,

DC.

konehead

Hi Deep cut

convert it to DC first with 4 high voltage diodes arranged as fullwave bridge rectifier, or jsut use a FWBR of around 600V rating...

then put a HV DC cap across the DC output of the FWBR...say 10uf or so....

then put a resistor across the the DC cap (also is the DC output of the FWBR too)

Experiment with resistor values...probably something like 100ohm might work for you with the high voltage of around 400V and small amps you have from those thin-wire coils....try to make the voltage drop around halfway down with the resistor value you choose...its nice to use a potentiometer here to easliy adjust resistance for a good value to find.

so you need to measure voltage ACROSS that resistor, and SIMULTANEOUSLY measure the  current going TO the resistor too - so you will need two meters, one measuring votlage, one measuring current.
You will find that ohms law will fit things nice doing this "lump resistive load" testing.. - such as, if you know the resistance and voltage, you can calculate the amps is going to be... but its good to measure voltage and current same time with a resistor like described to make sure what things are...

doing it as an estimation, quick and dirty, (like you did already) look at the maximum amps possible across the coils, I call this "crowbarring" the coil with an ammeter - voltage will be near zero doing this, but dont worry about it for now...

then see what you get in voltage across the coils with no resistance at all across it - I see you got around 400V I think....

so if you know the "maximum voltage unloaded" and also know the "maximum crobarred amps" across a coil then the "general rule of thumb estimation" is that you will get HALF the voltage with a resistive load, and you will get HALF the amps with a resistive load....so times (max volts/2)  X  (max amps/2) and that is approximatly what to expect....the BIG DEAL is what happens to the motor-draw in amps when you apply the resistive load.............proabaly whatever you make in watts, is going to be what the motor goes up in watts too - depends on how effecient things are....

but you got a SPEED UP with the coils crowbarred with AMMETER...thats VERY GOOD





garrypm

Gaz,

You can also do the measurement with only one meter.

Measure and record the voltage across your appropriately found resistor - per Kone.

Then disconnect the resistor and check it's actual resistance.

Using OHMS law V=I x R   - 

you now know V - volts
             also  R - resistance

then I - current must equal V divided by R.

too easy


1 + 1 = ?

Garry

DeepCut

OK thanks you two that's all very helpful :)

Thane Heins told me i should ahve the coils connected in parallel so i wil try that later also.

Unfortunately, shorting the output results in normal generator action, i'm not sure what ohmage resistor is used to measure in the 50 mA range on an analogue meter but it must be fairly low, so i think there's a tight load range that this nconfig can support.

Last night i tried a single, small coil on it's own, a 2 oz coil (the ones in the previous post are 1 lb), the accelerative rate of the speedup was ridiculous and the drop in mA was the best i've ever seen too. If it doesn't work out with these big coils i may wind them into lots of small ones, looks like it may be heading more and more toward a Muller-style setup.


Cheers,

Gary.