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Overunity Machines Forum



Thane Heins Perepiteia.

Started by RunningBare, February 04, 2008, 09:02:26 AM

Previous topic - Next topic

0 Members and 21 Guests are viewing this topic.

Charlie_V

QuoteYOU WOULD THINK THAT AT SATURATION THE VOLTAGE INDUCED IN THE COILS (OR LOAD - I HAVE TRIED 1 K DOWN TO 0 OHMS) WOULD PEAK WOULDN'T YOU? SO FAR IT HASN'T.

The voltage would peak if the core was saturating, but I'm talking about your shield.  If the shield saturates, then the magnetic drag on the shield would reduce.  The amount of flux change through the shield would remain the same, but because the drag has reduced, the rotor speed would increase and the current consumption of the motor would reduce.  The output current in the coil should increase a little too due to the increased speed of the rotor. 

I think all this is a good thing.  It would only be bad if your shield was saturating at lower rpms, or if the shield was saturated at startup.  Because if this was the case, then the amount of flux change the coil would see would be small and the coil's output would suffer. 

The biggest challenge I see is going to be trying to get the output power greater than the input power - ha, isn't that always the challenge?  Taking the case of the rotor spinning at 3500rpms, the motor is running 112V at around 2amps (based on the current shown in the video).  So the input power is roughly 224Watts.  The coil however has an open circuit voltage of 61.5V and a short circuit current of 0.034amps, so the approximate output power of the coil is 2Watts.  Even without back EMF, the motor is working too hard (either the drag on the shield or the motor itself is just too big).  However, if a 6V motor running at 300mA (and 3500rpms) can turn the shield, then the input power would be 1.8 and the output power would be 2.  Thane, didn't you mention earlier that you had used a bunch of magnets to balance the rotor?  Do you think your at a point where you could reduce the motor size or still too early?

Best Regards,
Charlie


CRANKYpants

Quote
I guess that would be the final proof, that you have beaten the Lenz law..
Thanks, regards, Stefan.

THANKS FOR THE SUGGESTION.

THE TROUBLE IS EVERYONE HAS THEIR OWN VERSION OF "PROOF".
WHEN LUC AND STEVE CAME TO THE LAB THEY BROUGHT LIGHT BULBS BECAUSE THAT WOULD PROVIDE "PROOF".

NOW WE HAVE LIGHT BULBS BUT STILL NO "PROOF".

SO WE PLACE A LOAD ON THE "CONVENTIONAL GENERATOR" AND IT DECELERATES - THEN ENGAGE THE HV COILS, ACCELERATE THROUGH THE LOAD AND SUPPLY SURPLUS POWER TO THE LOAD - BUT STILL NO "PROOF".

IN MY NEXT DEMO I AM GOING TO ACCELERATE THROUGH A LOAD WHILE WALKING ON WATER WHILE SIMULTANEOUSLY PARTING THE RED SEA AND RUNNING 100 METERS IN 9.65 SECONDS.

CHEERS
Thane

Charlie_V

To me, proof comes when the device can drive itself.  Whether you get extra power for loads doesn't matter to me.  If a machine can keep itself going until the parts wear out, thats proof enough for me. 

QuoteIN MY NEXT DEMO I AM GOING TO ACCELERATE THROUGH A LOAD WHILE WALKING ON WATER WHILE SIMULTANEOUSLY PARTING THE RED SEA AND RUNNING 100 METERS IN 9.65 SECONDS.

Meh, doing all that while standing on your head would be more impressive.   :D

CRANKYpants

Quote from: Charlie_V on August 17, 2008, 11:53:12 AM
To me, proof comes when the device can drive itself.  Whether you get extra power for loads doesn't matter to me.  If a machine can keep itself going until the parts wear out, thats proof enough for me. 

Meh, doing all that while standing on your head would be more impressive.   :D

WELL I AM UP TO 20 V @ 1 A (SHORTED) WITH MY NEW COIL USING 24 GAUGE WIRE (54 OHMS WORTH) AND THE MOTOR STILL ACCELERATES WHEN LOADED.  I AM GOING TO MAKE A NEW "PLATE" WITH LAMINATED TOROID CORE STEEL AND HAVE THE WHOLE THING ON A DC MOTOR WITH A BATTERY BY FRIDAY.

BEAR IN MIND I CHECK AT VARIOUS SPEEDS AND MANY DIFFERENT LOADS - I HAVE NOT BEEN ABLE TO DETECT ANY LENZ ACTION AT ALL.

CHEERS
Thane

CRANKYpants

Quote from: Charlie_V on August 16, 2008, 10:44:16 PM
The voltage would peak if the core was saturating, but I'm talking about your shield.  If the shield saturates, then the magnetic drag on the shield would reduce.  The amount of flux change through the shield would remain the same, but because the drag has reduced, the rotor speed would increase and the current consumption of the motor would reduce.  The output current in the coil should increase a little too due to the increased speed of the rotor. 

I think all this is a good thing.  It would only be bad if your shield was saturating at lower rpms, or if the shield was saturated at startup.  Because if this was the case, then the amount of flux change the coil would see would be small and the coil's output would suffer. 

The biggest challenge I see is going to be trying to get the output power greater than the input power - ha, isn't that always the challenge?  Taking the case of the rotor spinning at 3500rpms, the motor is running 112V at around 2amps (based on the current shown in the video).  So the input power is roughly 224Watts.  The coil however has an open circuit voltage of 61.5V and a short circuit current of 0.034amps, so the approximate output power of the coil is 2Watts.  Even without back EMF, the motor is working too hard (either the drag on the shield or the motor itself is just too big).  However, if a 6V motor running at 300mA (and 3500rpms) can turn the shield, then the input power would be 1.8 and the output power would be 2.  Thane, didn't you mention earlier that you had used a bunch of magnets to balance the rotor?  Do you think your at a point where you could reduce the motor size or still too early?

Best Regards,
Charlie



WHERE CAN I GET THE MOTOR YOU SUGGEST?

THANKS
Thane