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Overunity Machines Forum



Thane Heins Perepiteia.

Started by RunningBare, February 04, 2008, 09:02:26 AM

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0 Members and 3 Guests are viewing this topic.

OUman

Quote from: allcanadian on May 01, 2008, 09:48:08 AM
@OUman
Ok, take a 2 meter piece of wire and fold it in half, in you connect an direct current to the ends you would find the energy stored as capacitance would equal, Q(energy)=1/2 CVsquared. Now connect an alternating current the frequency is 150Mhz having a half wavelength of 1m, at this point the peak voltage in the middle of the lower wire corresponds with the minimum voltage in the upper wire as the wire is bent in a "U" shape. In this case the potential difference between these two points in the wire has doubled thus the equation for this instance is Q(energy)=CVsquared. Any variation in frequency from this resonant frequency will produce varied levels of capacitance as we are dealing with two points in a single wire under different conditions.

@AC, I don't think you quite understand the concept of capacitance. What you are describing would need to be modeled as a transmission line in order to describe its operation - in other words, a distributed capacitance/inductance/resistance. This in no way changes the fact that the capacitance does NOT depend on the current (nor on the voltage or the frequency etc).

allcanadian

@OUman
LOL ;D, Ouman I mean no disrepect but I have two choices, I can believe what you have read from a text book or I can believe the words of a man who was known as the greatest Electrical Engineer of all time---bar none--having hundreds of patents to his name. In Patent 512430 Nicola Tesla states-----
QuoteIf now, as shown in Figure 2, a conductor B be wound parallel with the conductor A and insulated from it, and the end of A be connected with the starting point of B, the aggregate length of the two conductors being such that the assumed number of convolutions or turns is the same, viz., one thousand, then the potential difference between any two points in A and B will be fifty volts, and as the capacity effect is proportionate to the square of this difference, the energy stored in the coil as a whole will now be two hundred and fifty thousand as great.
"the energy stored in the coil as a whole will now be two hundred and fifty thousand as great", I was wondering if you could explain how one would do such a thing?
And in another section the following quote---
QuoteI have found that in every coil there exists a certain relation between its self-induction and capacity that permits a current of given frequency and potential to pass through it with no other opposition than that of ohmic resistance, or, in other words, as though it possessed no self-induction.
So we could say a current of given frequency will pass with no opposition as though it possessed no self-induction, I wonder what might happen if a coil in an electric motor all of a sudden acted as if it possessed no self-induction where before it may have acted differently?.
As well you are making the asumption that the capacitive effect is limited to "only" the conductor, you may want to read the "Dr.Stiffler" thread.

Knowledge without Use and Expression is a vain thing, bringing no good to its possessor, or to the race.

OUman

Quote from: allcanadian on May 01, 2008, 11:38:42 AM
@OUman
LOL ;D, Ouman I mean no disrepect but I have two choices, I can believe what you have read from a text book or I can believe the words of a man who was known as the greatest Electrical Engineer of all time...

The mistake you are making is in mixing up the concepts of (a) "capacitance" and (b) "energy stored in a capacitor". These are not at all the same thing. He uses the archaic term "capacity effect" which may be what's confusing you.


JustMe

Quote from: OUman on May 01, 2008, 09:18:52 AM
The issue, as you well know, is one of integrity. Thane told us in his posting that this U of O prof checks these results on a daily basis before any of them are posted - and he is thereby co-opting the prof's reputation without the prof's permission. If it is not true that the prof is doing that checking, then Thane should not be telling people that he is.

I don't as-you-well-know anything of the sort. In fact, I don't even understand what your issue is.  How does Thane posting results read off a meter co-opt anybody's reputation? I've always assumed that Dr. Habash's position on the transformer tests would be similar to his published position on the generator which was something to the effect of "It accelerates, but we don't have any backing theory", and "At this time I can't support any claim." Receiving Thane's results in no way implies that he thinks they're perfectly accurate or that he agrees with Thane's overunity conclusions or any of his other theories.  This is simply ongoing research. If you find "check" too active of a verb, substitute 'reviews' or 'reads over' or whatever returns you to equilibrium on what is to me another mostly pointless point.

OUman

Quote from: JustMe on May 01, 2008, 02:26:53 PM
...I don't even understand what your issue is... 

My issue is that the posting quoted below is misleading. If you don't have an issue with that, fine. But I do.

Quote from: OilBarren on March 14, 2008, 07:11:18 AM
...WE HAVE OUR WORK (IMPROVEMENTS) DOULBE CHECKED EVERY DAY - BY DR. HABASH BECAUSE WE WANT TO BE SURE BEFORE POSTING THEM...