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Overunity Machines Forum



hho wirecell concept largest surface area question

Started by jikwan, February 22, 2008, 01:31:23 PM

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0 Members and 2 Guests are viewing this topic.

jikwan

just recently one of our top ranking hho experimenters made the statement:
"after so much testing, my conclusion is surface area determines output",,,,,,,,,or to that effect
fair enough-i can agree with that
my idea is that the surface area of a wire is great
compared to plate or tube it has far more surface area   (im thinking)
i want to get back to this guy and challenge him that plates and tubes are not the way to go
well i have some education in psychology philosophy etc   no training in maths
i cannot work out surface area 
i feel that considering the amount of material your putting energy into--wire is most efficient
im talking 0.5mm wire
any of you math guys help me on this?
thankyou in advance
zen is the art of seeing everything and noticing nothing

Mr.Entropy

Take a plate or tube, and cut it into wire like peeling an apple.  You create new surface area on both sides of every cut.

Cheers,

Mr. Entropy

jikwan

zen is the art of seeing everything and noticing nothing

ResinRat2

Research is the only place in a company where you can continually have failures and still keep your job.

I knew immediately that was where I belonged.

Mr.Entropy

Quote from: jikwan on February 22, 2008, 01:59:46 PM
c'mon man im serious

Me too.  I've proven that wire has more surface area per amount of material than bulkier tubes or plates, in a way that anyone can understand.  It's appropriate for someone without math training, is it not?

It you really want to know, the surface area of a cylinder or wire (not counting the ends) is pi*D*L, where D is the diameter and L is the length.  The volume is pi*D*D*L/4.  Area/volume is 4/D, so the smaller the diameter, the more area you have per unit volume.

The surface area of a tube (not counting the ends) is that of the outer cylinder plus the inner cylinder.  The volume is that of the outer cylinder minus that of the inner cylinder.