Roll on the 20th June

[ramset]

ARCHER what time is it now[where you are] do you ever sleep? its 10 17pm where I am USA just curious   Chet PS i've seen you at 5am my time on this thread

[sm0ky2]

ARCHER what time is it now[where you are] do you ever sleep? its 10 17pm where I am USA just curious   Chet PS i've seen you at 5am my time on this thread

you'd be suprised how many of us are chronic insomniacs   

[The Eskimo Quinn]

20 mins after midday on saturday, yes i get up at 5 am here and at night when i'm on its 5am there, i am currently inside coz i am dumping photos as the cam is full, and need to take pics for the upload tonight and to keep going so thats why i am on and off today.

[Rusty_Springs]

Hi All
Its 20 to 1 here and I like Eskimo Quinn are in australia
Take Care All
Graham

[badassdjbynight]

Crap!  I was editing my prev post to clarify it and the site timed out so I lost it.  So I'll try to remember it.  I'm not trying to monopolize this forum.. so this will be my last post for a bit and I'll let others chime in.

I want to move the discussion forward and not back. 

<quote=The Eskimo Quinn>But you must remember this is the missing point, go back to the poor old satellite trying to hit the earth but can't quite get there, be being pulled "all" the time to fall. unfortunately if you get this i won't confirm it until the 20th, but you need this key.</quote>

Archer's comment suggests a constant force to make it spin.  A pull toward the center of the wheel wouldn't cause it to spin, but one offset from the center would.  Gravity pulling on a weight is such a force at some positions.  From 12:01 to 6:00 the force (alone) would cause a clockwise rotation and from 6:01 to 11:59 it causes a cc rotation.  Other weights around the wheel counter balance it out and even out the force.  One of his hints was that's why there's 3 (not 4 or 2).  So the uneven number creates an non-balanced situation.  There are either 2 weights on one side (12:01-6) or the other (6-11:59).  That's what I was calling an offset...  If the three weights were left alone to find their own balance what position would they end up in?  One at the top and the other two at the bottom?  Maybe that's a clue.  But this is all basic wheel physics right? and I apologize if that's already been covered elsewhere.  Keeping the weight offset always on the 12:01 - 6:00 side would create a constant force.  But I'm not sure it can be done with sliding weights.

BTW.. I don't think I'm using newtonian math as I don't think I'm using any math.