Free Energy Revealed - Magnet Battery

[tinu]

Ok I am now getting 3.5 volts. I thought there was something wrong with my meter as it was only showing one volt when I turned it up to 20 voila 3.5. when set to 200V~ I get 6. and 80 microamps

Anyone here?

Hi,

3.5V is indeed much for a chemical reaction? First question would be if there is a possibility in your setup to have several galvanic elements in series. If you have, it may well be like 0.9V x 4. If not, at this point I?d say that your friend may be perfectly right. That?s because unless you live in a very remote area, it is most probably you have built a RF antenna; what?s not clear to me is which part of your setup act as a diode but that thought is not very critical as there are explanations at hand.

I suggest you try to recreate the 3.5V setup and then to place it inside a very good Faraday cage.  As long as your mobile phone indicates no signal, I?d say the cage is good enough. If you still read 3.5V, you have something there.
As alternative to a Faraday cage, if in the previous setup you?ve notice a very high sensitivity of the voltage in respect to the position of wires, your body etc., this is a good sign that 3.5V comes from RF and that by modifying some variables (i.e. capacitances), you somehow are getting close to resonance. Also, you may verify it by changing the voltmeter and nothing else. Usually, it is enough to use a different voltmeter that will require either a ?rearrangement? for indicating maximum voltage (resonance) or if placed instead of the first one will give much lower readings.
Finally, as a third alternative to check for RF noise, replace the whole setup under study with a simple antenna made of one turn of rigid wire connected to the leads of a RF diode. If you don?t have a RF detection diode, a simple 1N4001 will do it, although it will perform very very modestly. Connect your voltmeter to the leads of the diode using coaxial wire or, if not available, twisted wire. In a city where radio, TV and GSM towers are common, by playing with the radius of one-turn antenna and by finding an advantageous position for it, several volts is pretty easy to achieve. I?ve played with such a setup and easily found 2.8-2.9V and 60-70microamps (short circuit current), which is comparable with what you have.

Hope it helps.
Best regards,
Tinu

[xee]

@ 0ne
You do not need magnet. Metals have differing potentials. Two different metals separated by an ionic solution will produce voltage. This is how batteries are made. Check basic college chemistry books for explanation. Here are some videos showing battery with only non-pure water and two metals - no magnets. Note, will not work with pure water, need to have free ions in the liquid. Salt water will work.

http://www.youtube.com/watch?v=b-GAvA0YCxE
http://www.youtube.com/watch?v=6ZfsWwrivec&feature=related

[Jimboot]

Hi,

3.5V is indeed much for a chemical reaction? First question would be if there is a possibility in your setup to have several galvanic elements in series. If you have, it may well be like 0.9V x 4. If not, at this point I?d say that your friend may be perfectly right. That?s because unless you live in a very remote area, it is most probably you have built a RF antenna; what?s not clear to me is which part of your setup act as a diode but that thought is not very critical as there are explanations at hand.

I suggest you try to recreate the 3.5V setup and then to place it inside a very good Faraday cage.  As long as your mobile phone indicates no signal, I?d say the cage is good enough. If you still read 3.5V, you have something there.
As alternative to a Faraday cage, if in the previous setup you?ve notice a very high sensitivity of the voltage in respect to the position of wires, your body etc., this is a good sign that 3.5V comes from RF and that by modifying some variables (i.e. capacitances), you somehow are getting close to resonance. Also, you may verify it by changing the voltmeter and nothing else. Usually, it is enough to use a different voltmeter that will require either a ?rearrangement? for indicating maximum voltage (resonance) or if placed instead of the first one will give much lower readings.
Finally, as a third alternative to check for RF noise, replace the whole setup under study with a simple antenna made of one turn of rigid wire connected to the leads of a RF diode. If you don?t have a RF detection diode, a simple 1N4001 will do it, although it will perform very very modestly. Connect your voltmeter to the leads of the diode using coaxial wire or, if not available, twisted wire. In a city where radio, TV and GSM towers are common, by playing with the radius of one-turn antenna and by finding an advantageous position for it, several volts is pretty easy to achieve. I?ve played with such a setup and easily found 2.8-2.9V and 60-70microamps (short circuit current), which is comparable with what you have.

Hope it helps.
Best regards,
Tinu

Thanks Tinu for your feedback - I'm thinking I've probably discovered something that was already discovered by someone else :-) I'm not convinced re the Galvanic battery but my setup does lend itself to the series of galvanic battery theory. I'll test some more and report back.

Just on the Ed Leedskalnin stuff.... is there a general consensus amongst those who think of him as not worthy of study, how he built coral castle?

[Koen1]

Just on the Ed Leedskalnin stuff.... is there a general consensus amongst those who think of him as not worthy of study, how he built coral castle?

Not that I know of, but then again there is also zero proper suggested ways in which his proponents show how he somehow used his magic
insights into electromagnetism to do it. It is clear many Leddskalnin fans believe he did it by using his breakthrough ideas and was
able to produce magical OU effects andd levitation etcetera, but nobody seems to have any clear idea of how exactly that is supposed
to have happened, and anyone who has read all of Eds papers knows he doesn't describe anything of the sort. So there is basically
a consensus amongst both believers and non-believers in Eds ideas that nobody knows how he did it exactly.
There's a few odd photos that seem to show rusty parts of mechanical rotor-stator setups, which seem to suggest Ed simply built his
own generator, but nobody seems to know what the design was or how he used it. Since he doesn't show anything out of classical
electromagnetics in his experiments and papers, I would say he simply managed to construct a fairly efficient generator using
some permanent magnets and a lot of wire, and some rotor assembly that is set in motion by wind power which Ed had a lot of
in his corner there, and that he used this power to aid him in lifting and working the rocks in a mostly old school fashion.
But because nobody was around to watch him do it, and people only saw the finished product of moved and worked stones,
plus his apparently to many "groundbreaking" descriptions of his own imaginatory models of electromagnetism, people
seem to have concluded he must have been doing somethign "out of the ordinary", something quasi-magical, so obviously
he must have been a genious who had the true insight into the nature of magnetism and its role in the world. As if good
old Ed was Tesla or something, haha...

Ok I am now getting 3.5 volts. I thought there was something wrong with my meter as it was only showing one volt when I turned it up to 20 voila 3.5. when set to 200V~ I get 6. and 80 microamps

I don't follow what you are saying here...
So it was showing 1 Volt at some unknown or unmentioned setting of some mystery kind of meter,
then you "turned it up to 20", 20 what?... Please be more clear... You turned it up to 20 mystery units?
And then it read 3.5V...?
I'm not sure what kind of meter you've got, but my multimeters simply read the voltage there is to be measured,
I do not need to switch it to a certain level, it simply shows me the voltage.
It sounds like you have a really odd multimeter if the voltage it measures changes when you change a setting on your meter!
Then you say you set it to 200V~, which is also weird... Why would you measure things in a settung intended for 200V AC
when you know the voltage doesn't rise above 3,5V? And how can a setting at minimum sensitivity of 200V register a voltage
196,5 Volts lower than its threshold?
Are you sure you know what you're measuring? And are you sure your meter is correct, and that you're using it correctly?
Because it sounds quite strange to get totally different output values by just changing a meter setting...
It is possible that you read different values when switching between DC and AC, but I don't follow the "up to 20" setting,
nor the 200V threshold that measures way too low voltages.
I assume I have misunderstood what you meant to say, so could you please rephrase that?

[Jimboot]

Re am I sure I know what I am measuring? No :-)

But yeah my previopus post was confusing. My meter was set on 2, which I assume it will only read up to 2 volts. I tested a normal AA battery and it read 1.5 volts. My readings were getting towards the 2 volts range and then it simply read 1 which I assume is the default error reading for voltages above 2 volts. Then switched to 20 where I saw the reading of 3.5 and then also when I switched it up to 200.

An electrician friend asked me to see what the voltage was on the AC setting no idea what meaning it has.

THanks for the info on the Leedaskalnin stuff. Fascinating story anyway.

I have been testing the Gal battery theory this evening and there are a couple of things I don't understand.
1. When I place a neo (nickel plated I think) in water with a brass washer I get a reading of 0.01
2. When I place the brass washer upright on the neo with a wet piece of paper between I get a reading of 0.20

So a reading of 20 times more I find at odds with the chemical battery theory. I realise I must be missing something here.
When I place the brass washer near the edge of the mag with the wet paper between them the readings climb to 0.80. So on the face of it that supports One's explanation of funneling the energy IMHO.


3. I get readings of over 2 volts when the plastic insulation of the probe is between the mag and the probe itself. I don't understand how that is possible with a chem battery setup. Wouldn't we all be getting shocks if the plastic does not insulate at such low voltages?

I really do appreciate everyone's patience here for this noob :-)

Thanks