I tried to rebiuld a Don Smith Device

[TinselKoala]

Yep. Your assumptions are definitely leading you astray. Things don't quite work, actually, the way Don Smith says they do, and that's why you see people failing in their efforts to get their devices to work.

[Google]

Attached is the schematic.

Best,

[Jeg]

Yep. Your assumptions are definitely leading you astray. Things don't quite work, actually, the way Don Smith says they do, and that's why you see people failing in their efforts to get their devices to work.

I think the main problem is not in the given theory but in the lack of crucial details  for the complete understanding. ie resonating a coil to its natural resonance using lower frequencies. By the way did you check my waveform at hfsstc topic? 

[Google]

I did the experiment as attached here and found that there is no change in battery current draw when I shorted the secondary step down coil ends.

The system is not registering any load on it on shorting the secondary.

There is no earth connection used anywhere. Everything is on table and away from earth.
What is this supposed to mean.

Best

[Liberty]

I did the experiment as attached here and found that there is no change in battery current draw when I shorted the secondary step down coil ends.

The system is not registering any load on it on shorting the secondary.

There is no earth connection used anywhere. Everything is on table and away from earth.
What is this supposed to mean.

Best

If I may inject an opinion of the circuit: 

The circuit load consists of the flyback transformer and the two caps and the inverter.  As the caps charge up, they present a load to the inverter.  That is what determines your current draw in your circuit.  When the caps dis-charge after reaching sufficient voltage to bridge the spark gap, then the load to recharge the caps starts over.  So the load is really only recharging the caps after the spark dis-charge.  Therefore, shorting the secondary AB will have little effect on the current draw of the device.  I see no potential for OU in this type of circuit. 

The only way I have found to achieve OU (more power out vs. power in), is to be able to efficiently extract an external energy source or force that you don't have to pay back and add it to your device's output.  (Wind, sunlight, magnetism).