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Overunity Machines Forum



URGENT! WATER AS FUEL DISCOVERY FOR EVERYONE TO SHARE

Started by gotoluc, June 26, 2008, 06:01:38 PM

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hoptoad

Quote from: gotoluc on July 26, 2008, 01:10:15 PM
.... in the last video (just posted) he demonstrates a circuit design by Overunity user: capacitor70 and shows the power between gas and water.
Luc
http://www.youtube.com/watch?v=foytvHDYgEg
Very interesting and promising indeed ! .. KneeDeep

qiman


Hi everyone,

Here is how the water sparkplug circuit and Gray tube works. Some here assume when I compared the Gray tube to the water spark plug circuit by Luc that a spark gap is a spark gap...it is not...please read so you can see really what is going on...in my opinion and I do have experiments to back my beliefs.

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The HV from the coil moves through the HV diode to the + of the low voltage source to ground back to itself...it seeks ground through the diode. That diode is open. When the HV is off, take a volt meter and put the neg on ground and + on the hv diode cathode/output. You will see that you can measure the low voltage side's voltage potential on the output of the diode because the diode is open.

Many people think the diode is automatically closed and won't let the hv through but that isn't true. That is the whole point that diodes have reverse ratings...and if the diodes were automatically always shut, then the low voltage from the annode/input could never get through.

Also, the diode closing is not instantaneous...it is fast, yes, but not instantaneous...once the hv moves through the hv diode...it takes a bit of time for it to get the reverse current through it in order to slam shut.

The HV potential, which is the voltage gas (it is a gas composed of "particles" smaller than a hydrogen atom - smaller than an electron - very, very small fractional charges - Mendeleev's original periodic table of elements showed some of this) has MOMENTUM.

As it is moving, the HV diode slams shut and the voltage potential with its momentum slams against the diode...compressing it more and more...now that re-compressed potential...which is expanded 90 degrees from the wire has to go somewhere...the only path to ground as of now is the gap on the plug. That un-condensed/expanded potential is what causes the primary effect of the cold plasma.

Then, when voltage on the cathode/output of the HV diode drops below the annode/input of the HV diode, then and only then can LV source move out of it and over the gap.

The lv source is not the cause of the effect, it simply can boost the primary effect - which can be had all by itself with one small cap that is virtually empty when discharged to the primary.

Primary effect is that potential slamming against a diode.

Many think the simple hv spark jumping a gap is enough to ionize the gap to reduce the resistance enough to have the lv source follow it...that is simply a fairytale.

Only the recompressed potential against the diode's abrupt shut off can cause the cold plasma ionization that is necessary to allow the lv source to follow. At this circuit's scale of operation, this is all necessary to make these effects.

This is a method of "splitting the positive" that Bedini has shown for years in the open but nobody really got it. If I am wrong, I apologize and will correct all my explanations but until then, that's my story and I'm sticking to it until proven wrong but following the logic of all this, it is very consistent with what Tesla explained, it is consistent with other technologies that utilize this concept, etc...

Working of the Gray Tube

This will put what I'm saying into context with something that many people have studied but I am not sure anyone gets it. Many are convinced in all the free electron concepts in the Gray Tube, etc... McGratten mailed me a package about 7 years ago with that explanation but I always saw it happening in a different way.

The Gray Tube has a low voltage rod and high voltage rod. Low voltage rod has a diode on it that has the cathode/emitter pointed towards the gap. Low voltage source can be any low voltage source and Gray showed he used a 12v battery...the neg of that battery is connected to the neg of the HV capacitor at 3000-4000 volts and a few uf's. The + of the hv source goes to the hv rod.

(-)12vdc(+)diode->(gap)(+)3000vdc(-)

I have made the Gray tube analogy to the spark method and most have automatically thought that they look at 2 gaps and think they serve the same purpose. I'll show you why the 2 gaps have nothing to do with each other but why they are making the same effect. It is necessary to actually understand how the Gray tube works in order to see what the real analogies to the spark plug circuit are.

When the low voltage side is connected by commutator, whatever...the hv source immediately sees path to ground...it sees that the diode is open and has conductivity to the low voltage source which has conductivity to ground which is its own ground...it jumps and as soon as it moves through the diode for a small unit of time, the diode slams shut....only a small fraction of the hv potential made it through.

That hv potential from the cap slams against the diode and compresses against it very strongly forcing it to explode 90 degrees from the wire outwards...the only other path to ground it by going to the grids...through the electromagnet that pulses a magnet or other electromagnet to provide motive force on a motor to a + on another low voltage source and that lv source has a - that winds up being connected back to the hv -'s.

Take a balloon and push it flat against a wall. It compresses and the contents of the balloon wind up exploding 90 degrees perpendicular to the direction of original propagation.

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The gap in the Gray tube is simply a mechanism to get the HV to jump into a diode with a lv potential sitting on it so that it can move into it to have the diode slam shut to compress the potential against it.

The secondary discharge from ignition coil is a mechanism to get a HV to jump into a diode with a lv potential sitting on it so that it can move into it to have the diode slam shut to compress the potential against it.

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The Grids on the Gray Tube are the secondary path for the expanded potential to move to ground.

The ground on the spark plug is the secondary path for the expanded potential to move to ground.

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Here is what this method is:

You are giving the HV 2 paths to travel in order for it to move back to its own ground or relative ground.

1 path is a high resistance path
1 path is a low resistance path

---------------

The Gray tube high resistance path is out to grids back to ground.

The water sparkplug circuit's high resistance paths is over spark gap back to ground.

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The Gray tube low resistance path is through the diode to lv side back to ground.

The water sparkplug circuit's low resistance path is through the diode to lv side back to ground.

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1. The HV will choose the low resistance path FIRST
2. Diode slams shut expanding that potential
3. Expanded potential (electro-radiant event) has only the high resistance path left back to ground.

--------------

So when it is explained that the hv spark jumps the gap ionizing it to reduce the resistance of it and have the lv source follow it...is incorrect.

And seeing the analogy in comparision to the Gray tube, that popular explanation of how Luc's spark method works would be the same as claiming that this is how the Gray tube works:

The hv from the hv cap first jumps to the grids ionizing the air to reduce the resistance of it enough for the 12v battery potential to jump from the low voltage rod to the grids...all the while never needing the hv to jump the gap in order to slam against the diode.

We know the above is NOT how the Gray tube works but that is what people are claiming when they say the Spark plug circuit works by the hv simply going to jump over the gap to ionize it for the lv source to follow.

ramset

Whats for yah ne're go bye yah
Thanks Grandma

gazzzwp

New Circuit.

I was trying to create the radiant effect but using solid state switching instead of a relay charging a capacitor.

The circuit is shown below.  Some people should recognise the electronics part as it is a replication of Dave Lawtons D14 circuit.  The microwave oven transformer was necessary in order to achieve isolation between the HV and the electronics. Driving the ignition coil directly with the Field Effect Transistor (FET) simply destroyed the 100 ohm resistors.

With the AC switched off, the circuit produces a clean spark which can be varied in intensity and speed by using the potentiometers. 

With the AC switched on there is no discernable difference with the spark which I have to say dissapointed me.  I was expecting to see the radiant effect.  I even tried disconnecting two of the bridge rectifier diodes, suspecting that the spark was being dampened by a circuit through the diodes.  This made the bridge half wave instead of full wave, and the effective  DC voltage was reduced from 95 Vdc to about 30 Vdc.   Sadly, still no radiant effect. 

I suspect therefore that the radiant effect is due to the capacitor discharge.  I say this because apart from the higher frequency switching, that is the only difference between my circuit and the others.  If this is true then sadly I feel that it limits the usefulness of the radiant effect.

Any suggestions/ideas welcome.

Gazza

Gazza

AbbaRue

Your microwave diodes should be in series with the positive HV terminal right as it leaves
the coil, to keep the LV from shorting across the HV end of the coil.
Place them right between the HV out of the coil and were the pos.110v connects.
That should give you a better spark.
You have them in series with the LV lines. 
The 1N4007's are to keep the HV out of the LV end so you don't need them there.