URGENT! WATER AS FUEL DISCOVERY FOR EVERYONE TO SHARE

[lon92]

I done this before, but, I failed... My engine ignition timing was too advanced...
Here's what I do:

I wrap my ignition coil, just like yours in the picture, with, 60 turns of copper windings (the number was actually randomly picked).
Then, I feed the output signal through an opto-isolator.

The opto-isolator then, fed to my darlington pair, which's connected to my ignition coil.

The ignition coil will fires as the crankshaft turns. But, in my experiment, the ignition was too advanced, as I try to pull-start the engine, the recoil-rope pulled me back! Very painful.
Even if the engine was cranked, it will violently backfiring at the intake port. That was TCI of course...

You could modify it to work as CDI as you go...

For charging the cap, simplest method I've been using is by utilizing 'DC fluorescent lamp ballast' as my charger. You could use ZVS for more efficient operation, of course...

Good luck! 

[lots_of_lime]

Hello, I am new here and find this site interesting.
I took a look at the schematics at the start of this thread.
I understand how the circuit works, but wonder what the purpose of the diodes are.

-the inverter provides 120vac from 12vdc battery.
-the rectifier+the capacitor turns the 120vac into raw dc, about 160vdc.
Just a note here, the capacitor should probably be dc and rated for at least 200vdc, and find one with a low ESR, thats would be effective series resistance. the lower the ESR the faster the cap can charge and discharge.
-then the relay is switched, applying the 160vdc to ignition coil, when the relay turns off that is when the high voltage is produced on the output of the ignition coil. it a huge spike caused from the induction coils being inductors and they dont like changes, lol.

since ignition coils output spikes anywhere between 20000volts and up, from 12vdc.
yours will be spicing upwards of about 266000volts plus, lol. cause you are using 160vdc.
BIG ASS SPARK.

I'm not 100% sure what the diodes are doing, Have been trying to figure this out.
and also why so many in series, that makes no sense, one diode should be sufficient for whatever you are trying to do. all a diode does is allow current to flow in one direction.
maybe they are meant to be put in parallel to handle more current.

k, maybe i can explain what the diodes are doing.

at the moment the relay is switched to the ignition coil.
the capacitor with 160vdc across it is now across the ignition coil and across the spark plug- the voltage drop of all the diodes.again one is enough.
so the spark plug has about 155 volts on it.

now the output of the ignition coil will not see a high 266000 volts until the moment the relay switches back to the rectifier to recharge.
this is just the nature of inductors, remember from above.

so maybe the initial voltage of 155vdc on the spark plug gets it excited, don't now.
seems insignificant compared to 266000 volts.

would really like to know what happens without the diodes.

let me know if you see this different?

thanks rob
I have a lot more input, but let's start here.

[lon92]

Hi! 
Well, you're almost right, but, need more spices... 

-About the ESR, yup, you're perfectly right, but, also, lower ESR means longer lasting caps... I once use a cheap cap, very high ESR, last for about only 10 minutes of run time!

-160V DC charged cap dumped into the ignition coil? That's CDI, Capacitive Discharge Ignition. It doesn't make a 'huge-ass' sparks, but, aid the dv/dt rate. The spark arcs long, caused by higher voltage, but, usually, thinner, due to low amp... See? Voltage is nothing without current...

-The diode in the circuit used to channels the (relatively) 'high-amp side' to the 'high-voltage side'. Without the diodes, the hv-side would simply shorted.

-The diodes are in series because of the low reverse voltage rated by the diode itself. If memory serve me right, the diode used in the circuit have the reverse voltage rated less than 1kV. So, wiring them 10 in series would make them rated for 10kV. Enough for less than 1cm spark. (approx. 1kV for each 1mm spark gap.) Any less than this would make the diode act as an unintentional Zener diode... Lol!

-Actually, as you say, one diode could be sufficient enough, but, must be highly-rated. Like the microwave oven's diode. Rated at 20kV and 350mA. Usually, expensive too...

So, as conclusion, those darn diodes really needed. It being use as the high-current side channeler.
Remember, the CDI circuit made with mechanical relay are meant for demonstration purposes only! Not practical for any working engine...

For practical ones, I really suggest to use a 'real' CDI ciruit, which utilize SCR.

Cheers! 

PS: For the 'diode-less' version, you could jump to the Capacitor70 replication thread, by SuperGod, I guess...

[MrsNancy]

 Looks interesting and from reading the first few pages it sounds promising. Has anyone got an engine to run using this circuit so far?

I'm second year electronics and have not seen a chain of diode like that. It that to increase the voltage capacity?

[lon92]

Looks interesting and from reading the first few pages it sounds promising. Has anyone got an engine to run using this circuit so far?

I'm second year electronics and have not seen a chain of diode like that. It that to increase the voltage capacity?

I believe Dreamyear succeeded to to run his engine with the circuit. Look somewhere in Youtube.

About the diode, yup, it is to increase the forward-voltage of the diode.
Look in your diode's datasheet for rated forward-voltage.