Gravity Mill - any comments to this idea?

[hartiberlin]

Okay, now this step by step analysation has helped a lot to understand the
thermodynamical principle behind it and all the PV diagrams of the air which  went through
these cycles.

Now to optimize the cycles we must do the following:

Have no watercolumn above seawaterlevel, so we reduce
the negative impact of the hydrostatic paradoxon.
Instead have a nozzle directly at the seawaterlevel
inside the tube?s top, so it works like a fountain
and sprinkles the water 1 Meter at least out into an upper
reservoir at 1 Meter height.
I wonder how big must then be the buoyant force on the shuttle
to get the water  pushed out 1 Meter high behind the nozzle ?
Are there any forumulas to calculate this ?

2. We should try to calculate the needed energies to do this with a shuttle,
that has really only 2 different volume states and does not expand
or shrink with water deepth pressure !

So I will try to do this now.

[ResinRat2]

Hi everyone,

ooandioo and tbird, thanks for the info and kind words. I've been busy getting ready for my son's B-day party and am just getting back (snuck away from the wife) to reading the posts. A great deal of activity here today.

Hope tbird's and bastonia's attempts at contacting Mr. Herring work out.

Stefan, it doesn't seem like you read my first post, but check out this link to a drawing from Mr. Herring.

http://www.icestuff.com/energy/elsa/page_36_-_780.htm

It gives a simple way to recompress the shuttle. No electronics, no timers or switches. just a lever that can be weighted down by the water above.

If you get a chance read my earlier post.

Thanks everyone for all your efforts.

ResinRat2

[hartiberlin]

ResinRat2,
yes, let?s concentrate next on the recompression of the shuttle at the top.
To do this efficiently we really need to work this out with all the equatations.

I have to pause for a little, cause I have to take a bath and play with the tubes
and shuttle in it  and see, how the nozzle effect turns out and how much
force it needs onto the shuttle !

[pese]

recompressing , also good to understand with:
http://www.icestuff.com/energy/elsa/page_29_-_770.jpg

GP

[hartiberlin]

Mr. Herring has drawn some nice graphics,
but the problem is, that you have a special air pressure at
each deepth stage inside the shuttle and a different water pressure around the shuttle,
that has to be overcome, when you want to compress or push out the shuttle volume !


This needs real energy to do so, as you also have to change the
air pressure inside the shuttle. To change the airpressure inside the shuttle
is also not less energy requireful than to do it
with just a pump.

And for the pump we already know the equatations.

If you want to use the lever torquearm-combination you also have to calculate in the
distance you have to move the other side of the lever torquearm to get the desired
pressure, so to calculate the required energy you need to calculate the
forces x distance. If you move the shuttle pistons just 10 cms to achieve the different volume,
you have to move the lever arm at the other side, maybe 50 cm to have a 5:1 force multiplication
and then the question is, if the water is high enough, so you can do this 50 cm movement ?