Gravity Mill - any comments to this idea?

[hartiberlin]

Pranja, wouldn?t it be easier to calculate with your air reservoir in your shuttle to be not 0,5 but 1 liter ?

[prajna]

Stefan,

Yes I did calculate the force required in posting http://www.overunity.com/index.php/topic,570.msg11325.html#msg11325.

Again, neither tbird nor I understand what you are referring to when you say hydrostatic paradoxon do you mean 'paradox' as in http://scubageek.com/articles/wwwparad.html?

It would probably be easier to calculate things with a reservoir capacity of 1 litre.  Shall I redo the diagrams and all the calculations/explainations again?

[hartiberlin]

If we go with an  1 meter high exit tube instead of a nozzle at sealevel, no matter how small in diameter the exit tube is, this 1 meter height will need a much bigger volume shuttle at 10 meters down there, so this COP would be under 1 then and no overunity anymore.

[hartiberlin]

Tbird and Pranja, the hydrostatic paradoxon puts a heavy burden onto our design here. To make it clear:
as in my example the 1meter height  exit tube above sealevel puts a 785,4 kg weight onto the main 1 meter diameter water column, also if in the exit tube would only be 10 liter of water=10 kg ! Thus the shuttle bouyant force must be able to lift this additional 785,4 kg and not just the real 10 kg weight of the water inside the small diameter exit pipe ! think about it !

[tbird]

hi prajna,

stefan is hopeless when he's on his pda.  your link to the 'paradox' would have cleared this up easily if he had read it.

stefan when you're on the pda, for me, i will count you out of the loop.

prajna, how many people do you know that uses an absolute gage?  if we write everything factoring this in, we lose our simplicity.  so for the sake of simplicity, let's keep the pressure of water at 10m at 1 bar.  ok with you?

how 'bout it, can we do that?

haven't seen any responce to this question yet.  anybody want to step up?

tbird