Gravity Mill - any comments to this idea?

[ooandioo]

With the Cartesian diver we just convert a STATIC Weight force
into a moving work force=
usefull energy-work output !

What do you think ?

Regards, Stefan,

Isn't the deep the diver can sink in relation to the pressure you apply on the top of the bottle?
I think this will net out.

Andi.

[tbird]

[If I take the compressed shuttle to the garage the tire gauge will read 3.41 kg/cm2 or 3.41 bar or 49.4578686 psi (according to google's wonderful convert function.)
/quote]

hi prajna,  i'm a bit concerned about continuing to try to explain to you why you are still doing this wrong.  i'm worried i will offend you and you'll be put off the project all together.  my hope is you will figure out on your own so i won't have to sound negative any more.  i would suggest you figure this same example using guage pressure and see if it comes out the same pressure.  if it doesn't, you'll know something is wrong.  if you can get it to equal, explain to me.

Did you figure the suare cm by taking half the diameter and multiplying that by pi or by multiplying it by itself?  I hope the former since
we are dealing with the area of a circle rather than the area of a square.

i believe i did that part right.  our answers were within 10 square cm (i used rounded pi).  the numbers are; 25 x 25 x 3.14 = 1962.5 square cm.  this then would be mulitied by 1kg (i think that's what you say 1 square cm has at sea level) times 3.41, the number of bar you need at 10m (just for arguments sakes we'll say it's right).  this gives us this; 1962.5 x 1 x 3.41 = 6692.125kg.  your answer was 1731.2  kg.  did i miss something because of the metric system?

if i know your heart is in the right place (i think yours is), you can be pretty ruff with me.  i do have thick skin when i know you are trying to help me and not just be mean.  if anything in that last post didn't set right, don't worry about telling me.

if we keep up the struggle, we'll get there.

all parts for test are made.  just have to wait on the glue to cure and clean them up.  hopefully test tomorrow pm.

tbird

[tbird]

Quote
Did you figure the suare cm by taking half the diameter and multiplying that by pi or by multiplying it by itself?  I hope the former since
we are dealing with the area of a circle rather than the area of a square.


i believe i did that part right.  our answers were within 10 square cm (i used rounded pi).  the numbers are; 25 x 25 x 3.14 = 1962.5 square cm.  this then would be mulitied by 1kg (i think that's what you say 1 square cm has at sea level) times 3.41, the number of bar you need at 10m (just for arguments sakes we'll say it's right).  this gives us this; 1962.5 x 1 x 3.41 = 6692.125kg.  your answer was 1731.2  kg.  did i miss something because of the metric system?

hi prajna, just had a light go on in my head.  maybe we both are right.  when i did the calc, i used the size of the shuttle with only 5cm height.  this only requires a compression stroke of 2.5cm.  you use external compressing and feed it to the shuttle.  the size of the compression container could have a smaller compression area, but would need a longer stroke.  is that right?  it's been a long time since i actually worked with air compressors and the like.

tbird

[prajna]

tbird,

i'm worried i will offend you and you'll be put off the project all together.

No chance.  I'll be put off the project only when it is proved to my satisfaction that it doesn't work.  Today I proved to my satisfaction that it does work.  I have posted the proof at http://declarepeace.org.uk/elsa/ if you would care to check my work.  It does tell me that you need both strokes, up and down, and that you need to use a leverage to get it to work.  I haven't used any pressure units except kg/cm².   Sorry it is in metric but all the units are easy and I will add an example in imperial as soon as I get a chance.

I will have a think about calculating using gauge pressure and the light may dawn.  Thanks.  Oh, and my calculator has been set on hexidecimal rather than decimal for days too! Duh!

size of the compression container could have a smaller compression area, but would need a longer stroke.

Yes, absolutely.  It is like leverages: if you have a 2:1 ratio you apply twice the force by moving half the weight over twice the distance.

[tbird]

hi prajna,

you silver tongued orator!!  great job!!  this is what Mr. Herring has needed from day one.  to put all that on paper so anyone with half a brain can understand it is nothing short of genius!!  great job! great job!  if it doesn't fly now, no one really wants free energy.

I DECLARE YOU KING OF THIS THREAD!

how may i serve you?

tbird