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Overunity Machines Forum



A machine to convert gravity to mechanical energy # 2

Started by brian334, October 04, 2008, 01:08:18 PM

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brian334

M.
Thanks for doing the work.
Substitute depleted uranium for the lead and cut some holes in it for the cables and pulleys.



mondrasek

Brian,

Would you like me to give you another drawing with the weights thinned by 40% to represend 63 lb weight of DU?  Would you then be willing to show a design that fits all the elements inside the 1 sq ft. tank?  If not, I will stop wasting my time with you.  It is becoming clear to me that you don't really want to discuss your idea with the goal of learning anything.  Not that there is anything really wrong with that, only it's just not the reason I am participating in this exchange.

M.

jandell254

Hey

I did a few quick calcs but according to them it works, so obviously I made a mistake somewhere.  I only considered four stages where energy could be lost or gained:

1)  Energy is gained when the water pressure pushes the buckets into the air chamber
2)  Energy is gained as the tanks fall in the air chamber
3)  Energy is lost as the expanded tanks are pushed back into the water
4)  Energy is gained as the expanded tanks float upwards

Think of a similar machine to Brians, but with cubes that dont change size.  If this machine runs clockwise, and the cubes enter the air chamber at a low point, and exit at the top, say 2m higher, more work will be done by water pressure pushing the cubes in than pushing them out again.

If the cubes are 1m X 1m X 1m, and enter the air chamber at 10m depth, the work done pushing them in will be
pressure X area X distance = (1000 x 10 x 10) x (1 x 1) x (1) = 100 kJ.

The work done pushing them out at the top, at 8m depth, will be (1000 x 10 x 8 ) x (1 x 1) x (1) = 80 kJ.

From this it seems that work would be done by the machine.

brian334

Starting at the bottom the expanded tanks weight less than the liquid they displace and will float up. At the bottom the tanks have enough potential energy to lift the 63 lb weight all the way to the top. As the tanks rise they lose there potential energy and the 63 lb weight gains potential energy.
Because the tanks are accelerating as they rise the 63 lb weight is also gaining kinetic energy.
At the top the 63lb weight has both potential energy and because it is moving it also has kinetic energy.
Next at the top the piston lock is released and the external water pressure pushes the piston back inside the tank. Also at the top the tank flips putting the 63 lb weight back on top. The tank is now heavier than the liquid it displaces and will sink. As the tank sinks its potential energy turns into more kinetic energy for the 63 lb weight. When the tank gets to the bottom it is quickly pushed over by the transfer solenoid and abruptly stopped,
All the kinetic energy the 63 lb weight gained on the way up and down is converted to potential energy.
The 63 lb weight falls inside the tank pulling the cable moving the piston out of the tank. The tank is now lighter then the liquid it displaces and will float up doing work.

Also when the tank gets to the bottom the 63 lb weight still has about 11 inches of potential energy as it falls to the bottom of the tank.
The 63 lb weight falling 11 inches will increase the displacement of the tank by about 5 lbs.

At my website http://bsandler.com    there is a complete description of this machine, click on the tab at the top of the page marked Gravity Machine # 2

fritznien

Brian how much energy do you think it takes to flip one of your tanks end for end?
how dose that compare with the energy of the falling 63 pound weight?