Pulse Generator

[slayer007]

Here is a video showing the amp intake and voltage on the compasitor after load.
The load was from 110v nightlight.
http://www.youtube.com/watch?v=D4wFqJG_q5c

[slayer007]

Lidmotor made a video showing the generator running with a adjustable voltage regulator.
http://ca.youtube.com/watch?v=KwqMDBrF9wM

[Kator01]

Hi slayer007,

I would like to know if there is any voltage at the secondary-high-voltage-coil  of your ignition-coil ?
If there is no significant output-voltage then a test would be to remove the diode between collector and L1 and find out if there is a difference in the output to your cap ( charging-time, voltage reached )

I may be wrong but it seems to me that his diode does not make any sense as the negative kickback-emf from L2 takes the shortest path to diode which leads to the negative lead of the cap at the bridge as this is the low - impedance path while L1 means high impedance. I do not think that there is any current flowing through L1.


Regards

Kator

[slayer007]

Hi slayer007,

I would like to know if there is any voltage at the secondary-high-voltage-coil  of your ignition-coil ?
If there is no significant output-voltage then a test would be to remove the diode between collector and L1 and find out if there is a difference in the output to your cap ( charging-time, voltage reached )

I may be wrong but it seems to me that his diode does not make any sense as the negative kickback-emf from L2 takes the shortest path to diode which leads to the negative lead of the cap at the bridge as this is the low - impedance path while L1 means high impedance. I do not think that there is any current flowing through L1.


Regards

Kator

yes there is significant output voltage at the ignition coil.
If you remove the diode from the collector you get more voltage to the ignition coil.
And you'll get more voltage to but it will cost more amp input.
This way I was using the back emf from the first coil to go thru the second.

[Kator01]

Hey slayer007,

now the diode leads the back-current in a circle ( it seems ) through L2 again thus recycling that part of the energy via L3 directly to the bridge - so you could do without the ignistion-coil. This must give you more power back to the bridge. I think the power is divided up in L1 and L2. if you draw on the seconday of the ignition-coil you will loose more at the expense of L2-L3 to the bridge.

Have you compared exactly the power ( not the amperage ) of these two types of circuit ( with and without ignition-coil ) ?

Another point here is : the more diodes you use the more heat-dissipation you will get. Even if on uses very fast-switching flyback-diodes like UF 5408 you will have 3 volt forward-current voltage-drop which means heat-losses.Use ony the least  necessary amount of diodes.

Regards

Kator01