The Young Effect, my gift to the free energy movement!

[captainpecan]

Voltage with amps = watts. Voltage without amps = no watts. Power is based on watts or joules per second. You must have a watt gain to have any gain at all.

You must not have worked much with capacitors. It's not the same. You would be correct, most cases I agree. But with capacitors, you measure total energy. Which is 1/2 * Capacitance * Voltage^2.  Yes, I mention only voltage early. But later I show what your concern is about. The total energy.

Thanks for your input though.

[slapper]

captainpecan; thank you.

Still trying to figure out how you got 2 to = (1.1 * 2) plus do a little work on the side.

Thanks again.

nap

[captainpecan]

@captainpecan,

Nice work. I enjoyed the videos very much. Thanks.

Take care,

Michel

Thank you!  It's not easy trying to go head to head with 100's of years of physics. I did my best.

[captainpecan]

captainpecan; thank you.

Still trying to figure out how you got 2 to = (1.1 * 2) plus do a little work on the side.

Thanks again.

nap

Lol... I knew someone would be able to look past the equation crap and see the whole point of these video's... Good work...

[capthook]

Watched vid 4 again: your process is flawed

At the start you touch the leads of 3 capacitors together in hopes of getting a "control" figure.
You say "connecting them in parrallel with the least possible losses"

Again - I say the sparks flying when you do this is VERY lossy.

So comparing the 2nd test through the circuit - that is LESS lossy without all the sparks flying - as showing an energy gain is a flawed conclusion.

And you say "if you add the voltages together, which I say you can even though the equations say you can't"
That's your 2nd problem.
The equations are to determine an actual value of energy (joules : watts/second) - just adding the voltages to show a gain is wrong.