The Young Effect, my gift to the free energy movement!

[Pirate88179]

@ Chet:

Hard for all of us...trust me, I know.  As I said, I have been guilty of it but it serves no purpose.

Bill

[Charlie_V]

I liked the videos it is interesting 

[captainpecan]

I liked the videos it is interesting 

Thank you, I'm glad someone else found it interesting.


I am still a little hung on trying to understand the results of the last video I posted... I will post the link again, as it kinda got buried in the middle of stuff.
http://www.youtube.com/watch?v=vwp7podu06s

I have done many more tests since this video, and I am still getting interesting results.  All my new tests are using the motor to lift a weight, and measuring work done compared to energy lost.  I am still not seeing energy lost, directly related to running the motor.

The first thought is that due to Lenz Law, the fact that the motor runs at all, should show a loss of energy.  But in my tests, it appears that the only difference made in the circuit, is due to the added inductance of the motor coil, and the slight resistance increase.  Almost like the current doesn't even see the magnets in the motor, it just seems to push them out of it's way on it's way through. I know that is not a very scientific explanation, lol, but it does seem interesting.

Any thoughts as to why there seems to be absolutely no loss related to adding the motor in the circuit, even with a load?

[spinner]

...
I am still a little hung on trying to understand the results of the last video I posted... I will post the link again, as it kinda got buried in the middle of stuff.
http://www.youtube.com/watch?v=vwp7podu06s

I have done many more tests since this video, and I am still getting interesting results.  All my new tests are using the motor to lift a weight, and measuring work done compared to energy lost.  I am still not seeing energy lost, directly related to running the motor.

Hi, captainpecan!
You made a very nice videos presenting your ideas!
I know you don't  read posts or make responds to the narrow minded skeptics (like me)...
I do understand you! I swear!
"People who are saying it is impossible should not bother the other people who are doing it right now..." Or, something like that...(sorry, language...)

Regarding your experiments - you say you're showing the work done by your motor for free... Lifting weights? Yes, this is a solid proof method (i like it very much!)
But.. How much weight and how high? With a little speculation, I'd say "a few grams, a few centimeters high" (or anything in between)...

That would be in the order of miliJoules of useful work performed by a motor in your experiment. And I think you know that you're still "missing" at least 10-times more energy than that....

The first thought is that due to Lenz Law, the fact that the motor runs at all, should show a loss of energy.  But in my tests, it appears that the only difference made in the circuit, is due to the added inductance of the motor coil, and the slight resistance increase.  Almost like the current doesn't even see the magnets in the motor, it just seems to push them out of it's way on it's way through. I know that is not a very scientific explanation, lol, but it does seem interesting.

Any thoughts as to why there seems to be absolutely no loss related to adding the motor in the circuit, even with a load?

Your motor is in reality just a common inductive load (looking from the capacitors sides, or energy transforming processes)...
The energy converted to mechanical motion is very small.... Therefore, it doesn't really matter if the motor is blocked (fully loaded), or free spinning... Try it... The current flowing through the motor doesn't "see" the load at all... (it does but the result is almost negligible...) And, vice-versa, energy transformed to rotational motion (momentum) is to small to induce any usefull amounts of electricity back to the circuit....

That's why the final results are not very different when the motor is spinning or not, or if it is completely removed and replaced by a common wire...

At the end, the sum of all energy conversions should be Unity, and the practical results (all the energy accounted for) is still UnderUnity....

[tinu]

Thank you, I'm glad someone else found it interesting.


I am still a little hung on trying to understand the results of the last video I posted... I will post the link again, as it kinda got buried in the middle of stuff.
http://www.youtube.com/watch?v=vwp7podu06s

I have done many more tests since this video, and I am still getting interesting results.  All my new tests are using the motor to lift a weight, and measuring work done compared to energy lost.  I am still not seeing energy lost, directly related to running the motor.

The first thought is that due to Lenz Law, the fact that the motor runs at all, should show a loss of energy.  But in my tests, it appears that the only difference made in the circuit, is due to the added inductance of the motor coil, and the slight resistance increase.  Almost like the current doesn't even see the magnets in the motor, it just seems to push them out of it's way on it's way through. I know that is not a very scientific explanation, lol, but it does seem interesting.

Any thoughts as to why there seems to be absolutely no loss related to adding the motor in the circuit, even with a load?

Hi captainpecan,

Good movie, huge progress! Sincere congratulations for your desire to master the issue.
I’d appreciate that you’re now in the phase of fully grasping the physics behind it, in a correct way. Explanations were already posted, not just by me but by several other members, but here it is again, hopefully delivered at the right time and in a ‘digestible’ form.

You say:
“These tests indicated that there was a slight gain in energy, for using the motor. Not only that, the work motor does appear to be free.”

Several points that might help:
1. 44.6 compared with 44.8 is 0.4%. Please check the capacitor tolerance, that of the voltmeter and also the variability of force in pushing the switch and of making contacts of exact same characteristics each time you move the clips and so on (there are many factors, all contributing to total error). I’d put everything under 5% error margin or even 10%.
2. Judging as per 1, it is safer (and actually this is the case here) to say that “tests indicated that approximately the same amount of energy is dumped into capacitor 2, no matter if the motor is loaded or not.”
3. I’d be very cautious in using the word ‘gain’. Now it’s clear to you that, in its entirety, the system is facing a loss of up to 50% at each cycle.
4. Speaking of losses, it is well spent time to reflect upon the following fact: there is no way to lose more than 50% of initial energy for setups of this kind!!! Is it then possible to lose less than 50%? Surely it is. Your system already proves this possibility. Follow on for more.
5. As known, energy is not created, neither lost. So, speaking in terms of “energy losses” is not scientifically correct and it may create misunderstandings. Instead, one may better ask: Where did the missing energy go? It went into the environment, as heat.
6. A setup of the kind: capacitor 1 â€" black box (on one wire) â€" capacitor 2 may, in theory, transfer energy from 1 to 2 with and efficiency in between 50 and 100%. In other wording, it may exhibit an ‘energy loss’ (in the sense of 5 above) between 0 and 50%.
7. Considering 6, the setup under test does not have anything special; it’s in the theoretical range, although at lower limit (pretty worst in terms of efficiency). That’s why no electronic circuits use it. It would heat up and eventually catch fire.
8. What is heating up? In other words: Where is the energy transformed into heat? It’s on the plates of the second capacitor: it’s very important to understand it. Even in the ideal case (no resistance i.e â€" use of superconductors; perfect dielectric etc) the second capacitor is heating up. There (on the plates of the capacitor), part of the potential initial energy (which is voltage) is transformed into heat due to the movement of electrons (collision of incoming electrons, if you want to picture it easier although it would be scientifically incorrect), in the charging process.
9. Once the above is well understood, it will become crystal clear that a capacitor can indefinitely store a certain amount of energy and it can deliver it with 100% efficiency but it will pose efficiency issues only when charging it (and not at all when discharging it! discharging is 100% efficient).
10. How can heating be reduced (which is also equivalent to reduce the losses or to increase the efficiency) when charging a capacitor? It’s by applying at its terminals a voltage infinitesimally larger than its current voltage. That would require a variable voltage source that will slowly increase it’s voltage from 0 to 18.5V (as in your experiments). A battery doesn’t do that (it has constant voltage). A capacitor (capacitor 1 in your experiments) doesn’t do that either but exactly the opposite (it decreases its voltage from 18.5 to 9-10V), thus very low efficiency, close to the worst case.

In summary, to answer to the question of “why there seems to be absolutely no loss related to adding the motor in the circuit, even with a load?” I’d say that if the motor is not changing its functioning characteristic (i.e. the motor is the same ‘black box’ according to point 6  above), the setup remains the same whether or not you load the motor. The setup being the same, it will have the same efficiency, let’s say 56% in your case. Each cycle, only 56% of the initial energy will be reusable (half in capacitor 1 and half in capacitor 2 if they are of identical capacitance) and 44% is taken out of the setup. Normally, missing energy it is taken out as heat and the whole process might undergo unnoticed by the un-aware experimenter. But one may take the energy out as mechanical work (that’s what the motor does), which no matter if it is finally transformed into heat (motor stops due to friction) or just stored (i.e. motor raises some weights) it’s nonetheless the same 44% energy going out. Unfortunately the observation of mechanical work in conjunction with the un-awareness about silent heat does not mean it is something special going on there and certainly it is nothing there to give hopes for OU.

Please take your time in reading/understanding such long post with my hope that it will help.

Cheers,
Tinu