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Overunity Machines Forum



Joule Thief

Started by Pirate88179, November 20, 2008, 03:07:58 AM

Previous topic - Next topic

0 Members and 81 Guests are viewing this topic.

altrez

@TheNOP

Thank you for the insight. I did not stop to think about that!

Thanks!

-Altrez

gadgetmall

Quote from: altrez on May 22, 2009, 10:44:15 PM
@all

I have tested my 900kV stun gun on a 48inch tube and it works! Its only about 1/8 of normal brightness. This brings me to my next question. If in fact the stungun's transformer is producing 900kV what hope do we have of ever lighting a 48" tube with a JT to full brightness?

-Altrez
Hi . Its all about Frequency for a cold electricity Jt . We will get it with just a few milli amps ;)

Gadget
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Pirate88179

Al:

I hope you are right.  It does make sense to me about the "load" with the stun guns.  I was hoping it was some super transformer like the Fuji only a lot more potent.  Maybe it is not.  Gee, like everything else we have done, if we want to know, we have to try it.

I can't wait for my 650 Farad supercap to arrive.  Then, we will see what my EB/JT can really do. (Hopefully)

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen

TheNOP

Quote from: Pirate88179 on May 22, 2009, 11:44:04 PM
I hope you are right.  It does make sense to me about the "load" with the stun guns.  I was hoping it was some super transformer like the Fuji only a lot more potent.  Maybe it is not.  Gee, like everything else we have done, if we want to know, we have to try it.
the fuji are using a normal transformer while the stun guns are using an equivalent to a flyback transformer.

but regardless of the type of transformer, a load will change the output voltage.
it will be different from what you measure without a load.

take a diode and a resistors.
try 1k Ohms to start with.
connect them in series, then connect that to your jt's pickup coil.
measure the voltage across the resistor.
change the resistor for a higher value, 2k, then measure the voltage again.
try with a 100 Ohms.
with the 2k resistor the voltage will be higher.
with the 100 ohms it will be lower.

now try with a capacitor instead.
the voltage will go from low to high as the capacitor charge.
a fully charged capacitor is not a load, while an empty one is a full load.
the voltage will follow the charging curve of the capacitor.

take a 120 to 12 volts DC transformer, measure it output.
you will get more then the rated 12 volts when it is not under load.

the voltage drop are more drastic with flyback transformer, 35kv will usually drop to lower then 2kv.
it could even drop to as low as a few hundreds volts depending on the resistance of the "short circuit".

Pirate88179

NOP:

Thank you.  I just read something tonight that was very similar to what you are saying here.  I think I am starting to understand.

Thanks.

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen