Capacitive Power saver , C.P.S

[Creativity]

hey,
i tested it with 2x   1miliF 10V caps(electrolitic) and red LED.Voltage came from 2xAAA alcaline batteries in series.
I measured time in dark room untill i could not see any light from LED.
C1 only gave me 1m42s +/- 2s.
C1/C2 gave me 1m +/- 3s
C2 i couldnt se no light at all(doesn't matter how i connected the LED to it)
C1 around 40s.

i will have to repeat this measurements like 10 times to get the accurate average,now i did it only 3 times.
Interesting that C2 gives no power to LED...although when charged from battery it behaves like C1.

Can u try it on ur setup with like 4 LED's in series?

[gyulasun]

Hi Creativity,

I think you have to consider the red LED forward voltage drop (must be about 1.3 - 1.4V) that cannot reach C2 hence the voltage in C2 is already too low and this must be the reason you could not see any light when fed the LED from it. 
You can check this with a DC voltmeter how many Volts is left in C2 and also what is the voltage drop across the red LED when it is lit.  This way you would have a better insight to the energies left in the capacitors  (because there remains at least 1V or maybe max 1.2V in C1 too, LEDs do not consume current below their forward voltage).

The funny thing with LEDs in this particular test is that you cannot really use higher voltage in C1 to "counterbalance" the LEDs forward voltage drop because if you start with a high enough voltage, the initial current may exceed the the current capabilities of the LEDs and they get ruined.
Using more LEDs in series increases the forward voltage drops, unfortunately. Maybe using them in parallel sounds good,  this increases the current capability to survive at some higher starting voltages.

I have not done test with LEDs in this setup, will think on using other simple loads.

rgds,  Gyula

[gigawattgratis]

Dear Gyla

  DC motors is not the main, this setup is only for concept testing purposes, in fact if you want to work with high power DC motors or AC motors you must change switches for thyristors and the adequate controller for the high speed of the capacitors discharge and get overunity in a practical system,not only motors, any type of loads, however in this basical conceptual setup the main is get overunity and proof the concept

If you want get more performance in the lifter testing, you must use capacitors of more capacity.

Thanks Creativity for your led testings, I was using a DC motor for this testing and not bulbs or leds because light you can see go in dependence of your viewpoint, for a serious testing with this type of loads you must use a light sensor as a LDR or phototransistor for control the light level you want assign as "off state", however in a DC motor the off state is easy to see when the motor stop its spin, may be you have a trouble with the capacitor C2, because the expected is you get the same time than for C1, that is say 40 seconds, may be the voltage is too little, the suggested testing is at 12 VDC, 3 VDC is near to the critical voltage value for common leds, 20 mm leds fall the light about 1.5 VDC, however I can see you go for the right way and your testings is near to the overunity.

The question about the engineer thinks C1 and C2 are in other connection is open for you too creativity, what do you think?


Bye.

[Creativity]

probably we should consider the "default" test as best option.I mean resisitve load in calorimeter and check the temperature rise.

One question... just came to my mind.

@gigawattgratis

how did u measured the rise of the weight?please describe the procedure step by step.Have u let the motor to drop the weight down after every step?Was it like this:
discharge C1->weight risen.
let the weight go to it's start position.
discharge C2->weight risen.
let the weight go to it's start position.
and so on?


PS:capacitors r connected in series here,if u ask about step 1 with switch in position B.Actually i see it as discharging of C1 into C2 throught the resistor(motor).

[pese]

wit leds , you wil never find any "values" that you can "true" calcukate.
Only with filament bulbs (as resistor-load) , you will find , that you are
on an way -to learn -
G.Pese