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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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0 Members and 131 Guests are viewing this topic.

Magluvin

Hey Void

Flaws, yeah there can be and some bugs happen in unusual situations with configurations.

For 1, we only have a few parameters in inductors and transformers.   For example, a 2mh inductor on the sim, is it actually .42ohm like mine? 
Can All 2mh coils handle the powers that can be had in the sim?  Probably not

But this guy Falstad is pretty good at this programming stuff it would seem.  And for many of the circuits that the program was designed to do, I would have to say that it is in the ballpark. 
I ran a real test on the cap charge circuit in the first large circuit with all the loads in parallel, and the charge circuit works. It charges the cap to nearly twice the source. So if these functions of the inductor are correct, or even close, then I would venture to say that the function of the lrc is close also.
In fact the first circuit the prog starts with is an LRC and the voltage of the oscillator, from a source of 5v is over 10v. 

Im looking into other sims to see a comparison.

Thanks for checking this out Void.   I know many have doubts.  Its very understandable. In fact this is probably a bit taboo.   I just hope it sinks in to many that havnt experienced these things yet, and it is such common stuff.

I am working on an addition to the circuit that stops the cap discharge at near zero. If you put a diode across the discharge cap, in a way that the source doesnt conduct through it while charging the cap, when you hold the discharge switch, the discharge will stop .8v past zero. If the source voltage is high enough, .8v is a tiny sacrifice for some good accuracy.  But what I want is for the switch or mosfet/mosfet bank, to turn off at the zero point. 
If we release the switch and anything other than zero, the output suffers its full possibilities, but also if the switch is released before the first zero crossing, what ever is left, the source does not have to produce as much to get a full charge. So there is a possibility for some circuit control and regulation here to come up with.

Im kinda into small power at this time.  The big can come later as I get the feel for all this myself.

Mags



Magluvin

Also Void and All

I had shown a circuit code above with the comparison of in and out power. I chose the 2ohm resistors in order to try and show equal loads for power measurements to be clear.  It is possible that if I used .2ohm resistors, that the power consumed by the resistor alone, may not be the total power in the lrc as a whole.   Point being, the 2ohm resistors are most likely the weak link.   Otherwise, we need to measure all components to see what the total power dissipated on each side, in/out, really is as a whole.   If the resistor is very low, its power dissipation will be very low due to low voltage across it, so now wee would need to see the power dissipated into the inductor to get a true circuit potential.

If we have 2 100 w bulbs in series, on 110v, then each would get 25w and the total would be 50w dissipated.
If we have a 500w bulb in series with a 100w bulb, the 500w may not even light up, but the 100w may be near to full power.  But just the measurement of the 100w bulb will not give the total power consumed, so what ever the 500w bulb is consuming, should be added to the 100w as a whole.   But the 100w should give a pretty good indication of high majority of power consumed as the 500w filament will be at much lower ohms than the 100w when full current is running and the 100w is hot and high.

Mags

void109

Mags,  thanks for taking the time to post your findings, its always a pleasure to read.

I agree the guy at falstad is definately pro (I'm a developer myself, and the guy has large math/engineering skills).

I tried altering your design in a few ways to automatically shut off current flow at 0 volts as well, with no success, I tried it using diodes as well as a combination of 555 timers and mosfets and transistors - with no luck - the problem I was having is the cutoff time was just too long.  In order to get the ringing in the RLC output portion of the circuit, it apparently needs to be an almost instant cutoff.

Thanks much

Magluvin

Hey Void
The diode is a ruff way of doing it, It does the cutoff near zero, but the switch still needs to be opened on or near that time also.
Im thinking what we need is a comparator circuit that measures the caps voltage discharge and use it for a trigger to cut the switch(mosfet, etc)  It all has to be quick. But with what we have to work with today, I think we can gitter done.

The basics of the so called amplification is here. I say so called due to it is the end result, but not conventional for most.  Now the switching needs work. And now that I get the feel of the lrc, how it works, and the required switching, The switching does not seem that hard to do after all.

Some say the mosfets wont do what Teslas did exactly, but it will work.  Lets say that a mos transistor doesnt have quite the on resistance or timing we are looking for, so what, if the input suffers a tiny bit, the output will suffer a tiny bit, but the power ratio should be similar. And the sim is showing we can get some amplification at lower voltages and freq also, and thats what I am going for.

Cold electricity is cool, lol, but I cannot say that is what we have here. Yet anyway.  Just inductors with inertial effects and caps that tune the bounce in the circuit.  Basics.

As I come up with the switching circuits I will upload the codes.   Ill send the diode on the cap tonight to demonstrate that its function is desirable here, and then work on the How To Switch  it circuit.

Thanks for giving it a shot, I could use a another good mind to help me out. =]

BBL

Mags

gsmsslsb

Hello Mags and all
If you want switching at zero have you considered an SCR.
Just a thought
GSM