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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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0 Members and 106 Guests are viewing this topic.

br549

Quote from: gyulasun on June 07, 2013, 06:03:23 PM
Br549,

No, I did not say your input power calculation was wrong. It was correct. (What you say as an example for the "input power" (0.006.52 / 1= 0.00004225) just gives the power dissipated in the 1 Ohm resistor due to the 6.37mA input current taken by the input coils, right?  (the 6.37mA may have been 6.5mA now that you measured 6.5mV voltage drop across the 1 Ohm).  The 6.5mV across it is not the input voltage to your transformer's input coils.

However, the 1 Ohm resistor directly across the output coil terminates the output, it is the load, just like your ammeter was in your video: with its 1 Ohm inner resistance the ammeter served also as a load of 1 Ohm.  And in the video you measured 1.5V rms voltage across your ammeter terminals and later you measured 0.055V rms across an outside 1 Ohm resistor. How can you explain this?  The 1 Ohm inner resistance of the ammeter and an outside 1 Ohm resistor should give the same load to the output coils, hence the rms voltages must be the same across both (within a few percent).

Gyula

Gyula:
I am cleaning up my setup, I will go through the measurement steps again. I will use a 1 ohm 5W resistor on both the input and output, and measure the voltage across them. I'm just about finished with a new H-Driver board that I hope will give a cleaner signal to the transformer, and will check the meters for accuracy, and do it again.
Thank you: br549

gyulasun

Hi,

Thanks for your efforts anyway and I hope you do not repeat or modify anything just because of my 'questionings' your measurements but because you also have found: something gives problems in measurements.  And you may have found it.

Gyula

br549

Quote from: gyulasun on June 09, 2013, 05:00:08 PM
Hi,

Thanks for your efforts anyway and I hope you do not repeat or modify anything just because of my 'questionings' your measurements but because you also have found: something gives problems in measurements.  And you may have found it.

Gyula

The attached document shows my second test (didn't have time to do a video, I'll be away from my lab for the next week or so) . I replaced the power supply with battries. The new H-Bridge Driver works much better. (I used different FET Drivers: TC4420 (Rated at 6 amps)) with same oscillator circuit. Much cleaner output. Used a 1 ohms 5W resistor as a load on the transformer output and one in series with the transformer input . I also confirmed to accuracy of the 2 meters with a Martel IVC-222HP Certified Voltage and Current Sorce. They seem to be accurate, both voltage and current. At least on the DC scales.
Thankyou: br549

br549

Quote from: br549 on June 10, 2013, 05:46:18 PM
The attached document shows my second test (didn't have time to do a video, I'll be away from my lab for the next week or so) . I replaced the power supply with battries. The new H-Bridge Driver works much better. (I used different FET Drivers: TC4420 (Rated at 6 amps)) with same oscillator circuit. Much cleaner output. Used a 1 ohms 5W resistor as a load on the transformer output and one in series with the transformer input . I also confirmed to accuracy of the 2 meters with a Martel IVC-222HP Certified Voltage and Current Sorce. They seem to be accurate, both voltage and current. At least on the DC scales.
Thankyou: br549

Sorry: Posted the wrong thing: This should be it:

gyulasun

Hi br549,

I think the output AC voltage amplitude across the H-bridge driver board's "output to transformer" pins should be known to estimate the input power to the transformer. What you show on the input voltage meter (7.4mV) it is the voltage drop across the 1 Ohm resistor (placed in series with the input) so the input current seems to be 7.4 mA. To learn about input power you need to know how much voltage drives 7.4 mA current into the primary coils.

I understand you supply the H-bridge with 4.5V DC from the 3 AA batteries but you need to measure the square wave's rms value across the "output to transformer" pins of the H bridge board and multiply it with the 7.4 mA input current to have an input power estimation. 

I would suggest 2 things to evaluate input AC rms voltage. 

You may wish to use the HP voltmeter which in the picture now shows the input current, just disconnect it from the 1 Ohm series input resistor (leave the resistor in series as it is now) and hook the HP up to the 2 pins of the H-board's "output to transformer".   

And you may wish to check the AC rms input voltage by an oscilloscope too, across the H-board output pins, this could double check the input voltage. 

Needless to say, the input current 7.4mA should not change during these measurements of course and no problem you will not see it during the input voltage measurement. However, please keep an eye on the output AC voltage (63.974 mV) because if it changes more than a 1-2 percent when you disconnect and then connect the HP voltmeter and/or the scope to the pins, it will be a good indication of grounding issues between the measuring instruments. 

Gyula