ENERGY AMPLIFICATION

[d3x0r]

Just for kicks lets go down this path
Lets say voltage runs outside the wire like the magnetic field from pos to neg, when the inductor is powered up the voltage builds up in the inductor and moves no further, when the inductor turns off the voltage is released and surges on to the negative post.
would this fit the reactions we see in an inductor.
It would except for the fact that the inductor changes polarity when the power is turned off.

So we have to look at electron flow and the A vector field to understand whats happening.

If the positive source was disconnected, that end of the coil would become negative ...


Just because a neon is lit at both ends, and has a constant connection does not mean it changes direction... a spark gap is lit at both ends... but the flow will be one directional; especially if formed with a point and a dish (vacuum tube rectifier) which will only flow one way; but is lit through the gas to both sides...


I dunno I guess I've run out of examples; since you insist that not one of the examples resembles current in a coil well... leading a horse to water and such...

[Dave45]

If the polarity of the rebound (bemf) cannot be changed from pos to neg we are in trouble, if this is the case then we need to start looking at electromagnetic and static combinations for free energy.

But the air purifier model does give hope because of the pos and neg ion clouds that form around the electrodes, using this analogy a pos pulsed coil will return a neg rebound.

Electricity has to be bidirectional if it wasnt the the ion cloud would only form around one electrode and would have a deficit on the other.

And a transformer transfer's voltage as well as current to the secondary.

Tesla used an open ended coil off the secondary to bring in more pressure as he put it, what if we do both off the primary to bring in neg current and off the secondary to bring in pos voltage.
I have the coils wound for a dc pulsed system and would like to see the reactions before changing to the mazilli circuit.

[Dave45]

If the positive source was disconnected, that end of the coil would become negative ...


Just because a neon is lit at both ends, and has a constant connection does not mean it changes direction... a spark gap is lit at both ends... but the flow will be one directional; especially if formed with a point and a dish (vacuum tube rectifier) which will only flow one way; but is lit through the gas to both sides...


I dunno I guess I've run out of examples; since you insist that not one of the examples resembles current in a coil well... leading a horse to water and such...

We all have to follow our own path, I hope one of us finds the answer.
My views are very flexible I dont really set everything in stone yet when we can do that we have found the answer.

[Dave45]

You cannot pulse a primary with dc and get dc from the secondary without diodes, this alone should show you that the primary changes polarity and it does it at every 1/4 and 3/4 cycle in ac because ac is a coil being pulsed with alternate dc pulses to each end of the coil.

[d3x0r]

You cannot pulse a primary with dc and get dc from the secondary without diodes, this alone should show you that the primary changes polarity and it does it at every 1/4 cycle in ac because ac is a coil being pulsed with alternate dc pulses to each end of the coil.

only says the secondary changes polarity...


I have to take back a little; if you disconnect positive that end will go negative, and once the field is gone, and has collapsed, then it can start rebuilding in the other direction from that ---- to the less - near ground... which will cause a backwards current... but at that point, it'll be the third phase on the secondary (already rose, already fell, and is falling again, which is a rise of current in the opposite direction)


Adding diodes to the neon/coil from before will either prevent it from working at all, or it will work.... which direction is the diode so it works?


Edit; hope I have a chance at a quick edit; I guess the neon will work too... but after the field is done, and all charge is stored in the capacitance of the diode, then the current will go backwards through the coil and fire across the neon in THAT direction; one way just adds an extra step.