ENERGY AMPLIFICATION

[MarkE]

A neg electron flow creates a pos current flow
The bemf from L1 is pos will the bemf from L2 be neg.
Notice there is no electron path from the battery allowed to enter the load loop.

Dave once again: When you interrupt the current path to an inductor, the inductor terminal voltage will flyback in a direction that tries to maintain the current flow.  If no path is available then the voltage rise is limited only by the parasitics: particularly capacitance until the rising voltage breaks down insulation or the switching device.  You have drawn yet another circuit where one inductor switches into another.  Depending on how fast the transistor turns off and the inductor values, the transistor will be destroyed by overvoltage stress.

[Dave45]

D1 provides the alternative path, which is also an indication of the polarity of the bemf from L2

[MarkE]

D1 provides the alternative path, which is also an indication of the polarity of the bemf from L2

Dave, no these circuits will not work unless you turn the transistors off very slowly.  You can download a free SPICE simulator:  LTSPICE from Linear Technology.  If you download that and learn to use it, then you can play with any ideas that you want and see what will really happen.

[Dave45]

The only alternative is to flip D1 which would indicate that the current has reversed which doesnt happen.

[MarkE]

The only alternative is to flip D1 which would indicate that the current has reversed which doesnt happen.

Dave, I don't know what logic drives you to believe that either circuit is useful.