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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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F6FLT

Quote from: partzman on December 08, 2018, 10:59:33 AM
I will agree here as all my tests of circuits using parametric inductance and capacitance have been conservative up to this point in time.  However, Gorchilin claims gains are possible with parametric inductance using partial cycles.  See-

http://gorchilin.com/articles/energy/RLC_5?lang=en

Unfortunately my calculus skills are lacking so I'm unable to determine if his theory is correct and I haven't attempted any type of build.

I'm curious to know if you have ever considered the TPU by Steven Marks?

Pm
Hi Partzman,

I don't like math but Gorchilin's equations are not too hard.
The voltage at the inductance terminals is usually noted (1) UL=-L.dI(t)/dt when L is constant.
Here Gorchilin considers that L depends on I, so he writes :
UL=L(I) It    "It" with a dot above  means the time derivative dI/dt, and t an index because I is time dependent, so we retrieve the right equation (1) with L depending on I, in occidental notation:  UL=L(i).dI(t)/dt  (Gorchilin doesn't care the sign which normally is negative. I suppose that he want to calculate the energy which is proportionnal to UL² so the sign would not be important).

But when L is not constant, equation (1) is false. We can't just replace L by L(I). When L is not constant and depends on I which depends on t, then L depends also on t and we have :
UL=d(LI)/dt = L(t).dI(t)/dt + I(t).dL(t)/dt  (see here)

Gorchilin makes the same mistake with the capacitor, using a voltage dependent capacitor C(U) so he writes UC=C(U)dU(t)/dt, instead of :
UC=d(CU)/dt = C(t)dU/dt + U(t)dC/dt

However I'm not totally sure that his method couldn't fit the traditional method, I think he's wrong but it's to be verified, but not necessary because there is a much obvious error after that.

He has an integral on U for the capacitor, an integral on I for the inductance, and an integral on t for the resistor.
Now the worst : he sums the three energy integrals as they were independent, instead of summing first (UC+UL+UR)I(t) so that the sign of UL becomes critical, and integrating on t after, to get the total energy and compare it to the integral of U(t)I(t) of the generator. So I'm not surprised he can find OU!


leonelogb

Tito L. Oracion  :-* Did you see my post? how many primaries and secondaries more I need  ::)  ::) Two?  ;D ;D ;D  8)

Quote from: Tito L. Oracion on November 28, 2018, 05:33:07 AM

No! :o  but multiple primaries and multiple secondaries in the  legs, these legs are primaries and secondaries ok. :)
its up to us then if what we want to do to the secondaries, if we want parallel or serie, thats basic ok. :)
and for me its not the best design though. :(  sorry bud. :(


@ all
i cannot be here always anymore, cause i'm busy. sorry. cannot reply more.


remember: the way to the truth is don't kill the dipole.  :) 8)
how to do that?: well just make a strong charge separator. thats it.  ;)
OF COURSE: THE MANY THE BETTER. 8)


bye everyone
God bless and GOODBYE AGAIN ;D
ETIOTS ;D

seychelles

The best energy amplification is Mr Skinner gravity machine.
So simple yet nobody have replicated it as yet.
https://www.youtube.com/watch?v=mEat-8zOjlE

bringdownthezog

Quote from: F6FLT on December 08, 2018, 04:56:48 PM
I am very impressed by your argument. Obviously, Maxwell is wrong. I haven't seen such a solid theory since the Hollow Earth theory.

Imaginary MEG. Maxwell is not Bearden.

bringdownthezog

Quote from: densama on December 05, 2018, 11:46:37 AM
https://overunity.com/17986/current-amplifier-as-key-to-the-free-energy/msg526593/#new
https://yadi.sk/d/dH-xE-qW3HFWDX
https://www.youtube.com/watch?v=smPr7CFHGhw&feature=youtu.be
http://mazeto.net/index.php/topic,10002.msg96812/topicseen.html#msg96812

thanks to x_name41 :o :D
it's hard to hear the voice within consistenly and walk on it ... but i always try to trust it first
there's real fight between my carnal mind and the voice.

sorry 4 everything ...buddy

Fabulous. Thanks for the update.  ;)