Howard Johnson Replication Tube Claim

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Here's a set of Relative Sizing and Spacing values, based on my estimating equations.  It's driven off of rotor width.  You can use these equations/values to be sure your magnet set is roughly similarly matched to the set Mylow used in his original Running Motor.

Chase212327

Nice .. helpful :-)
Would it be possible to get same info for his new seven-six disk config ..his last video ? ?   

Cheers
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[Chase212327]

Nice .. helpful :-)
Would it be possible to get same info for his new seven-six disk config ..his last video ? ?   

Cheers
Queue

Highly unlikely, unless we could get diffinitive, detailed measurements.  Are the rotors the exact same rotors he used in his Original Running Motor?  Did he at all change the gaps between his rotors, in order to adjust for Sterling's new stator?  Too many unknowns with this New Running Motor (at this point).  And it sounds like Mylow has stepped back now too. 

Chase212327

[Chase212327]

Queue,
Your rotors are 9.6mm wide and one inch tall.
How does your stator compare?...

C:  Rotor Width                9.6
G:  Stator Total Width       25.6
H:  Gap Between Rotors   3.2
J:   Stator Pole Width       6.4
K:  Stator Opening          12.8

BTW, the stator should be one inch (25.4mm) tall too, to match your rotor height.

Chase212327

[Grimer]

http://www.youtube.com/watch?v=SHCgXWN-15A

On watching this video one can't but help getting the impression that one is watching a long line of SMOTs with inertia taking the place of gravity in carrying the rotor from one position to the next.

I feel therefore that Omnibus is absolutely right to bang on about the SMOT in the way he does.

The problem of continuous running is therefore one of closure. Has Mylow by fiddling about arrived at just that combination of magnet strength - or rather lack of it -, disc inertia and group spacing which enables him to close the gap? It seems quite likely.

By breaking up the magnets into groups he has cut out all but first order interactions.

If you remember when you first encountered calculus, even the first order interactions are cut out let alone the higher ones.

Think of those children's puzzles where you have to count the number of triangles. The individual triangles are easy but then there are the triangles made up of groups of triangles and the triangles made up of groups of groups of triangles. Finally there is the biggest triangle of them all, the highest order interaction. That is what is stopping the closing of the circle. That has to be eliminated by making the groups so independent that only the first order interaction, the driving interaction is significant.

I seem to remember that the same destruction of high order interaction takes place if you try to magnetise a very very long iron bar. You don't simply get a north pole one end and a south pole the other but there's all sorts of weird stuff going on in between.

If I'm right then the Germans will be in London by Christmas (to bowdlerize my most popular quote from the Battle of Britain     ).

[spinner]

Oh, hey, Frank!
It must been a year or more since we have our last "talk."..
Good to See you!


Yep, the basic "SMOT" problem (or, all the previous work) is playing a role here....
Of course, it's up to anyone to find an answer for themself...

.........

Hey, we have a professional here, in this very thread!
Omnibus is an expert to deal with a "SMOT" type answers....   

CoE and similar stuff.... I believe You  know his "mantra"...?

Anyway, good to talk to you!

Cheers!

"spinn3er"