Sjack Abeling Gravity Wheel and the Worlds first Weight Power Plant

[fletcher]

When you work out that vertical distance is the only salient point, then you'll realize that distance horizontally introduces a time factor as a function of slope - potential energy is simply unrealised kinetic energy in waiting therefore we can dispense with it here since they start & finish at the same heights - that means that the yardstick for Ke is velocity from [1/2mv^2] - the velocity at any vertical height regardless of the slope & horizontal displacement is identical.

That is because the ACCELERATION from the gravity field is CONSTANT & always acting vertically i.e. non changing, with NO horizontal component of thrust whatsoever - therefore the vertical height velocity [aka Ke] will be the same at any height regardless of path taken because any side thrust is completely independent of gravity acceleration.

There is no violation of CoE - you have simply failed to account for the frictional forces of the slope providing an upthrust component aswell as a horizontal component which affects the time & distance covered derivatives but not the Kinetic Energy aka velocity.

This has lead you to misinterpret & misrepresent average velocity as a violation of CoE & is meaningless in this context.

[Omnibus]

McFly, HELLOOO!!!!!!

Different potentials along the length of the course-different speeds.  Get some graph paper. (Though you probably wouldn't know what to do with it )
http://www.tubechop.com/watch/50539

Not at all. Same potential for the two balls. I already explained that.

[Omnibus]

@fletcher, read some standard text and learn what kinetic energy is before repeating over and over again your confused understanding of it.

Also, if friction bothers you observe the problem in absence of friction as variational calculus does.

[Omnibus]

When two balls start at the same level and end up also at the same, although lower level, the decrease in their potential energy is one and the same no matter along what path they've reached the end level. What has happened inbetween is immaterial regarding their potential energy loss--it's the same for both balls.

[matrixman]

Different potentials along the length of the course = different velocities. Still gonna monkey back no?

KE is mass times velocity squared. This value is the same for both balls at the end of the journey.

So since the kinetic energy is the same for both at the end and since there are different potentials for each before the end, where does this leave you? Still need this spelled out for you?


You make me feel like the guy in the blue, whick makes you...
http://www.youtube.com/watch?v=sn8MkrSO1n0