Sjack Abeling Gravity Wheel and the Worlds first Weight Power Plant

[Omnibus]

The weights are NOT attached to the wheel on the left hand side.

The weights are leaning against the wheel on the left hand side.

The weights are in slots and are free to slide closer or further from the axle on the left hand side.

M.

Doesn't matter. How they reside at that point, as part of the wheel, makes no difference. The torque will be the same at this very position, no matter whether or not we have glued them at this position, attached them to the wheel through multiple surfaces or had them loose as in this case. The torque will be just the same. The only thing that makes a difference is the presence of a guide.

[stgpcm]

Cyan vectors are the components of the tangential component of the weight vector and are applied where the center of mass is, lying on the Grey line. Obviously, the Grey line (where the center of mass at all positions of the wheel resides) runs parallel to the physical guide. This is simplified presentation of the wheel we're discussing, focused only on the forces that act at this given position of the wheel.

yes, I know that's not where the guide actually lies, however the simplification shows the problem: one of your vector components acts in a direction that causes the weight to act against it. the actual guide is either above the weight in which case the rightward vector intersects it; or below the weight, in which case the leftward vector intersets it. 

[Omnibus]

yes, I know that's not where the guide actually lies, however the simplification shows the problem: one of your vector components acts in a direction that causes the weight to act against it. the actual guide is either above the weight in which case the rightward vector intersects it; or below the weight, in which case the leftward vector intersets it.

No, guide is sideways. Besides, the rightward or leftward vector isn't under consideration when we talk about torque. Torque is only the product of the normal component (pointing downwards) and the length of the arm.

[hansvonlieven]

yes, I know that's not where the guide actually lies, however the simplification shows the problem: one of your vector components acts in a direction that causes the weight to act against it. the actual guide is either above the weight in which case the rightward vector intersects it; or below the weight, in which case the leftward vector intersets it.

And it all adds up to -1 

Hans von Lieven

[Omnibus]

And it all adds up to -1 

Hans von Lieven

That's not perpetuum mobile. That's nonsense. I've spelled out very clearly the criteria for a setup to be perpetuum mobile, go back in the thread and read them.