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Overunity Machines Forum



Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

Started by Pirate88179, June 27, 2009, 04:41:28 AM

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0 Members and 80 Guests are viewing this topic.

a.king21

Zeitmaschine: It cannot be coaxial cable because that would be electromagnetically shielded. It has to be heavily insulated (against static) high voltage cable.
High voltage cable is quite capable of handling a couple of kilowatts safely. Say 10 amps, Maybe 15 amps at mains voltages.
It may be coaxial cable with the braid stripped off. TK does this all the time.

Zeitmaschine

Since I have this photo just at hand: It shows a very nice work of Mr. Flim-Flam!

Most likely the whole device is accommodated in box one - and only in box one. Box two passes the grid power. The three switches are there at best to switch the power on and off. Box three passes the output power through the dummy coil to the lamps. Box four passes the ground cable to box one.

No noise, no heat, no vibration, no radiation, no adjustments, no nothing. Any further questions?

Yes: What fits in a box approx. 20×20×10cm that can generate 2KW of electric power? :(

FreeEnergyLT

a.king21

Quote from: Zeitmaschine on October 26, 2012, 08:30:15 PM
Since I have this photo just at hand: It shows a very nice work of Mr. Flim-Flam!

Most likely the whole device is accommodated in box one - and only in box one. Box two passes the grid power. The three switches are there at best to switch the power on and off. Box three passes the output power through the dummy coil to the lamps. Box four passes the ground cable to box one.

No noise, no heat, no vibration, no radiation, no adjustments, no nothing. Any further questions?

Yes: What fits in a box approx. 20×20×10cm that can generate 2KW of electric power? :(

FreeEnergyLT
Pulsed transistors producing radiant energy maybe?

frankidel

Quote from: a.king21 on October 26, 2012, 07:05:04 PM
Zeitmaschine: It cannot be coaxial cable because that would be electromagnetically shielded. It has to be heavily insulated (against static) high voltage cable.
High voltage cable is quite capable of handling a couple of kilowatts safely. Say 10 amps, Maybe 15 amps at mains voltages.
It may be coaxial cable with the braid stripped off. TK does this all the time.

Hi A.king, i just watched video 200W from stivep, the 100kw turkey, the 2kw from 2007, and all the ground are braided copper wire ( or aluminum wire ) like you said, could he want static discharges ??? in the centre of a coaxial cable.

elementSix

Anyone think this can help
Houston, that just the proper order of operations when working the equations that include Q. L which inductance is in Henrys, that's always ideal. Winding resistance is the loss, and if you use a 1000 feet. The primary of T1 is just over 1 foot long, and 1000 feet of 9AWG wire has 0.8077 ohms of resistance. So, if XL = 1 ohm at 1MHz, Q = XL/0.0008077. Q is only a figure of merit, I've heard it called Quality, Flyback Value, and a few other things. Once, you've calculated the Q, you've included the wire loss. So, if the winding resistance were 1 Ohm, Q would equal one.

I want to use that primary. But, it really looks like I'm going to have to decrease the power in the first stage in order to keep the cores from saturating in later stages. Saturation isn't really the problem anyway, with each stage a step up. The current per stage is lower and lower, the voltage is higher and higher. Current will saturate a magnetic core, voltage won't. Voltage will cause an eddy current when it breaksdown and causes are between granuals of metal that the core is composed of.

I solved the modeling problem, if you went to those links. I even know that I gooffed in the number of turns on T2 and T3. There's a design rule of thumb, and when I use it, I don't screw up. So, you're really seeing me flunk my own self test. Not completely because I know where my mistakes are. The Output Impedance of T1, is used to calculate the minimum inductance value of the primary required for T2, the output impedance of T2, is used to calculate the value of inductance of the primary of T3. The simple rule of thumb is that the inductive reactance of any resonant stage following the first must be at 2 times greater than the output of the previous stage.

Using ideal component values is typical in designing any circuit. Because, it gives you an idea of what the circuit will be operating like. You calculate losses once you've selected all of your components. One capcitor is not the same as another, and the quality has everything to do with it. If it's only good up to 100 volts and your circuit is going to be operating at 1000, you can't use no matter how many amperes it can handle. If it can handle 20KV, that doesn't mean that it's any good at 100 amperes if that's how much current is passing through the circuit by design. The leads will heat up once you get past 1 ampere. So, you'd need a doorknob capacitor. Some heat up internally due to the thickness of the plate and they can't the handle 1 ampere without heat expansion causing the value to change during operation. It's not a tuning capacitor, and it's not a controlled change, and will throw off your center frequency. If you wanted everything tuned to 1MHz, that capacitor won't stay the right value.

I don't believe that you understand the solution, or the problem. We have enough of the right components to operate that circuit design all the way up to 2.5KW with available components all day long, and well over Unity.
Well, I know this much, my wire diameters are fine. Ran a few calculations and T2 could work if you stacked 4 T-400-2, the dash two is a red core, and it's powdered iron. And T-2 if the winding pitch is adjusted to distribute the windings evenly winding on the stack as if it were a solenoid, and not using the cores for a toroid style winding, the primary of T2 can handle all of the energy and will only rise 3°C. That's ideal for lighting, especially the unloaded secondary design.

T3, most likely will require 1 to 2 more cores, even though that may not make any sense. The quartz tube coil at this point would be wrapped around the outside diameter. If you made the coil the smaller than that, it would fit inside cores and you would have put the light somewhere the sun didn't shine. I had said before that I would have to wind on the edge of one of these cores to actually calculate inductance per turn. So, it would be easier to wind with coated wire, and measure the inductance every few turns, until it reaches the proper value.

T1 is 1 to 100, T2 is 1 to 4, and T3 is 1 to 2 and the secondary is left open for the bare wire, and the bulb is just a gas at a pressure of 0.01 torr. Even though I had revise this somewhat, you do have the design rules of thumb.

Input voltage times 1.414 equals the voltage across the primary of T1, current times 1.414 equals the current through T1's primary.

Output impedance is then 10000 ohms. XL of T2's primary must be 2 times greater at 1MHz, or 3.18 mH. Then you multiply the current and voltage again by 1.414 due to the capacitor in parallel with T2's primary. T3's primary should be at 18mH. At that point, I would switch to MPP cores, or Metglas in the same arrangement as defined for T2. It should have a higher permeability in order to reduce the number of turns of wire required. Only MPP and Metglas cores operate cool enough, and Metglas should outperform MPP at those frequencies if the design request is sent to the manufacture for the core size and operating frequency. It would be custom and you would want it's dimension to match the T-400s.