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Overunity Machines Forum



Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

Started by Pirate88179, June 27, 2009, 04:41:28 AM

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verpies

Quote from: zcsaba77 on February 08, 2013, 04:11:53 PM
Brass thick is matter?
If McFreey's operational principle is correct, then yes.
Partial directional polarization of beta decay products and incomplete magnetic confinement of fast charged particles inside the brass disk, can be compensated for by a wider or more massive disk. 

In other words, it is much easier for fast charged particles to escape from a thin disk, than from a thick disk.

Farmhand

Quote from: SchubertReijiMaigo on February 07, 2013, 07:09:50 AM


More on parametrics: One admitted theory to get FE is parametric variation of C or L in respect to Time as per E.Dollard said.
For example you need to switch periodically from a low L (charge) to a high L (discharge).
The energy is equal to E= 1/2*L*I^2 in coil, so the energy gain is E= 1/2*DeltaL*I^2 where DeltaL = Lhigh - Llow.


Mathematical example:
Charge a coil at 1 Henry at 1 amp = 0.5 Joule.
Switch to 10 Henry always at 1 amp and discharge = 5 Joules.
DeltaL is 10-1 = 9
So Egain is 1/2*9*1^2 = 4.5 Joules.


If the energy needed to change parameter is lower than the energy gain then you have OU !
The real question is how to change parameter with virtually no energy input (that's a question that I ask myself for nearly two years now.)
Saturating a trafo won't give a DeltaL =/= 0 because during charge and discharge the process is symmetric.
Hypothesis:
1) Shorting a coil during the charging process (Llow) (maybe waiting 5*L/R that the current stabilize and mutual induction "disappear" due no current variation anymore) then opening the short just before discharging (Lhigh) is a possibility.
I have watched Ufopolitics radiant circuits, unless a very unusual phenomena enter, I don't see how a coil who is charged and discharged without parametric variation (DeltaL = 0) can be OU, his radiant circuit are basically a buck-boost converter that you can find easily in the market.
2) A rotor with alternating magnetic and non magnetic part in a magnetic circuit (stator) will be also a good start as per Ide Osamu capacitance motor reveal.
3) Using mag-amp at condition the control winding doesn't dissipate too much power and no coupling between power and control winding.


So if all those device like TK, Don Smith use parametric you should be able to see coil shorting at the charging cycle and opening during discharge, by using spark, electronic control and so on.


SRM.

Well call me crazy, but if you charge a coil so that it stores 0.5 Joules, then change the inductance to 5 Henries there is still only 0.5 Joules for the coil to discharge.

If what you propose was true it should also be possible to do the reverse, charge the coil with 0.5 Joules then change the inductance to less and get less energy out,
but where would the energy that did not come out go ? Same with the increase of inductance to attempt to get more energy out where would the extra energy come from ?

It's kinda like saying if we charge a 50 liter compressor tank to 20 PSI then somehow change the tank to a bigger or smaller the energy in the compressed air would change.
Would it ? If the tank size was halved it would mean the pressure would be greater, but it would take energy to compress the air more as the tank was made smaller.

Cheers

MileHigh

Excellent points Farmhand.

I will quote myself because it is relevant to your discussion:

<<<<<<<<<
But just for fun here are two classic circuitry examples for you to ponder with respect to your model and how it fits in.

You have two ideal inductors of equal value.  Imagine one has one ampere of DC current circulating through it, and we put a ground reference on the left terminal of this coil.  Call it "coil1."  So the coil is in a closed loop with one amp of current flowing through it.  Initially the second coil is simply disconnected.  Then imagine then we add the second coil in series with the first coil, we "switch it in" to the single ideal coil circuit instantly.  So we have this:  Ground - coil1 - coil2 - back to ground.  Also, there is no magnetic coupling at all between the two coils.  In the real world on the bench you put the two coils at right angles to each other to have near-zero coupling.

What happens at the the moment the "switch in" happens?  The answer is that the current instantly drops to 0.7071 amp (for ideal coils).  And the potential measured at the connection point between the two coils goes infinitely high for an infinitely short amount of time.  Before and after the spike the voltage at the junction point is zero volts.

With non-ideal coils in a real-world circuit on the bench, the current will also nearly instantly drop to perhaps a little bit less than 0.7071 amp.  At the connection point between the two coils, the voltage will shoot up in a spike to hundreds or perhaps even thousands of volts.  The pulse width will be very narrow, and the higher the voltage spike, the narrower the pulse will be.
>>>>>>>>>

MileHigh

Zeitmaschine

Quote from: verpies on February 08, 2013, 08:19:26 AM
Each such plate has the volume of 5000cm3. Now, the density of brass is 8.5g/cm3, thus 5000cm3 of brass has mass of 42.5kg.
42.5kg of brass costs $425 in Chicago. Two such plates will cost $850 + cutting/lathing costs - leftover scrap value.
Why not make a smaller one? An electric motor works just as well regardless of its size, a transformer works also just as well regardless of its size. But free energy may only appear above a certain physical size? Very odd.

Quote from: elementSix on February 07, 2013, 09:00:16 PM
I believe that in order for TK's system to work, it has to start out low and work its way up to full power.  He has to have a circuit controller inside of the 2004 can.  It can work something like a SMPS.  In a way..  For the receiving coil to stay in resonance, the circuit controller has to adjust the input frequency and the wave power.  It probbaly operates at very high frequency for that exact reason.  So that the much lower frequency that the recieving coil gets, could be equal to or around the Earths Resonant Frequency or the 44Hz that the Frequency counter showed
This is much too complicated to come across. My suspicion is that the effect of the Stepanov device (transformer in state of resonance) and also the Kapanadze effect (could both be the same principle anyway) were discovered by accident while connecting a power factor correction device the wrong way or by playing with a self-made one.

Quote from: verpies on January 23, 2013, 12:20:23 PM
Off the top of my mind:
W1 - 50 turns of 18AWG wire (over the same core half as W2 and W3)
W2 - 15 turns of wire (over the same core half as W1 and W3)
W3 - Copper strip (0.5mm thick) 1 perpendicular turn around one-half of the core (insulated from the core, as wide as will fit snuggly)
W4 - 150 turns of bifilar winding (not over the same core half as W1/W2/W3)

HF: 300kHz - 2MHz (suspected dependency on DC-offset @ LF/W2), 10VP-P, 250mA sinewave or sawtooth waveform
LF: 45Hz - 55Hz 10VP-P, 250mA sinewave waveform, with adjustable DC-offset
HF to LF frequency ratio: Integer (most likely)
HF to LF phase relationship: Unknown (most likely fixed)
W1 to W3 phase relationship: Unknown (suspected 90 degrees)
C1: Capacitance adjusted to form LC resonance frequency with W3 equal to the HF frequency
C2: Unknown.
Load: Mostly resistive (150W incandescent light bulb)

Note: Alternatively HV short nanopulses can be applied at W3 (without C1) for kW power output at W4.

I would appreciate any corrections to the above...
And I would appreciate any ideas about the basic principle of the above, because it could be also the Kapanadze principle.

Let's see: The secondary coil is easy, it is a resonant circuit, bifilar wound. But how does the primary side work? The primary side consists of two coils and a copper strip. Essentially these two coils and the strip can do nothing else than magnetize the ferrite core (in a distinctive way). One coil is connected to a higher frequency (382KHz) and the other coil is connected to a lower frequency (50Hz). Now if the resonance frequency of the secondary coil would be half the higher frequency of the primary coil then this would be appropriate to excite a parametric resonance in that secondary coil.

If both frequency generators are not synchronized with each other (and I don't think so) then the frequencies are floating (see below). That means when both waves are positive or negative they add up, if one is positive and one is negative they cancel each other.

Therefore, what happens if the current of the summed waves saturates the ferrite core of the primary side? As long as the magnetic field is in the linear scope (determine by the 50Hz wave) the superimposed 382KHz wave can excite the secondary circuit. This secondary circuit resonates and its magnetic field tries to influence the primary magnetic field in reverse. That would be the behavior of a normal transformer. But since the primary core goes subsequently into saturation it cannot any longer be influenced, but nevertheless the resonant oscillation in the secondary coil still goes on. Hence the energy of this oscillation has no other way to go but to the load, as long as the saturation state of the input side continues. The transformer works unilateral during that interval. It is essential that the secondary coil can freely oscillate without damping due to a saturation of its core.

So the working cycle would be: Excite the secondary coil during the linear scope of the primary core, cut off the way back from secondary to primary by means of the saturation interval of the primary core. Do this with a frequency of 50Hz.

The main issue here seems to be that the energy needed to drive the primary core (abruptly) into saturation is less then the magnetic energy (oscillation) that gets trapped in the secondary core because it can't flow back to the primary core. Hmmm ...

Now what could be the meaning of the copper strip connected to a capacitor? It is simply a shorted winding. And a shorted winding generates additional current which generates an additional magnetic field which drives the primary core even deeper into saturation. The same should happen when a spark hits the copper strip.

Anyway I have still the problem how to do this with an ordinary E-core transformer with its core in one piece (like Kapanadze's one). If I short a coil of such a transformer (generates high current) then at best the whole core will go into saturation, not just the primary side. Hmmm ...

Quote from: Grumage on February 08, 2013, 03:48:24 PM
I have been testing this thing off and on today with all sorts of unusual results. The amplifier module is an off the shelf Mono audio amp rated at 40 W. First thing was that by replacing said module for an 18 W unit, there was no voltage gain. So I went back to the 40. You can see noise on the scope trace, I wonder if this is what is acounting for the double voltage output? Another unusual trait is that after a short time the voltage starts to drop back to something more expected. If you then change up the frequency range and come back you get the same bright bulb dimming back. It is as though the Ferrite needs a ping as I call it!
I would call it saturation what the ferrite needs.

Try to pulse-saturate the primary ferrite (not necessarily with a spark). Would be interesting what happens. ;D

Regards

verpies

Quote from: Farmhand on February 08, 2013, 08:09:31 PM
It's kinda like saying if we charge a 50 liter compressor tank to 20 PSI then somehow change the tank to a bigger or smaller the energy in the compressed air would change.
Would it ? If the tank size was halved it would mean the pressure would be greater, but it would take energy to compress the air more as the tank was made smaller.
That's logical thinking BUT...
Are you sure the same principles hold on a microscale as on macroscale?
The analogy between gas molecules and atomic spins, which are responsible for magnetic field in a ferromagnetic core, fails at the microscopic level.
When you increase the tank, the air inside does work on the expanding walls of the tank and the pressure and temperature of the air molecules decreases.  If you keep doing that, the air will eventually cool to absolute zero and the process stops.

However, you will not be able to stop the atomic spins by extracting energy from a ferromagnetic.  The spins will regenerate and persist perpetually.  That would be equivalent to air molecules never being able to cool down.