Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

Started by Pirate88179, June 27, 2009, 04:41:28 AM

Previous topic - Next topic

0 Members and 266 Guests are viewing this topic.

Zeitmaschine

The spark in that experiment IS the Over Unity!

The input ammeter stays on the same value regardless whether there is sparking to ground or not. Hence the constant DC input is dissipated as heat in the inverter and transformer with or without the spark. That energy input from the battery just creates the condition necessary for the vacuum energy to flow in. It is the Tesla's energy sink for tapping the ambient medium!

The question is: why is there no ground current measurable on direct connection but only when sparking? Is this basically because the spark converts the vacuum energy into light, heat and sound? So if there is no conversion taking place of the vacuum energy into a usable (visible) form of energy then the vacuum energy does not show up in the first place?

Think we are close. ;D ;D

Do we need some energy in order to pump the petroleum out of the ground? Can we then see the energy hidden in the petroleum without igniting it?


Khwartz

Hi Zeitmaschine. Would be Very Nice!

BTW, have you the measurements which show the actual overunity? And if yes: with which pocedure and caracteristics of equipments? Please.

Indeed, this claim is as hold as Tesla but it is about to get the corresponding results...

Cifers, precised data, COP measurements, have you?

Regards.

Zeitmaschine

Since the spark dissipates energy in form of light and heat, and since that energy is obviously not taken from the battery, then that energy has to come from some other place, namely the environment.

When the one side of the spark gap (during each 50Hz cycle) is positive (lack of electrons) then it attracts electrons from ground electrostatically on the other side. But because of the spark gap there is a spark which dissipates that energy instantaneously. When there is no spark (direct connection) then there is nothing that can make use of that energy. Then it's like a battery connected to nothing. Without sparking a voltmeter shows a few hundred volts across the spark gap. Most likely that reading is too low because of the internal resistance of the voltmeter which is not infinite.

Correct me if I'm wrong: In an ordinary electric circuit there can't be current without dissipation of energy at the same time. You can't have current in an electric circuit without the dissipation of light or heat or magnetic waves etc. That means, if there is nothing in the ground connection that dissipates (converts) the energy (makes use of the energy in some way like a spark) then the energy is there (like in a battery without a connected load) but it can't be measured.

How to measure the voltage of a battery without creating a closed circuit (putting load on the battery) through a measuring instrument?


Vortex1


NickZ

  @ Zeitmaschine:
   The diagram that you posted is showing an input of almost an amp, even without a load. So, that circuit is not a self runner, as without this input there is nothing. 
Where is the over-unity that you are mentioning?  Output measurement, or load?

  If you give the same circuit 220v input from the mains, what is the difference?