Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[callanan]

More very important information from JLN.

"To find the imbalance of ground potential produced by the telluric currents, I have built and I use a kind of tellurmeter, see below some photos and the diagram of my device..."

Also please see the latest updates in his website.

http://jnaudin.free.fr/kapagen/k32.gif

[replicator]

More very important information from JLN.

"To find the imbalance of ground potential produced by the telluric currents, I have built and I use a kind of tellurmeter, see below some photos and the diagram of my device..."

Seems to me it is rather an electrometer than a "telluric meter". Shouldn't be to check telluric currents at the ground between two points?

[nappolean]

i got this from http://jnaudin.free.fr/kapagen/replications.htm


http://yfrog.com/0zkapagenschematicjlnjuneg



oops i didnt read calla post my bad

[baroutologos]

Interesting thing Naudin begun to  things.

By the way, you are conviced of OU going on there. Is it? Are you sure for that? 90% efficiencies are quite misleading according my experience.

Has Naudin claimed OU yet?

EDIT: Replicator has posted a very good suggestion for an initial overview regarding the OU matter

EDIT2:

For those involved a bit in Tesla technologies and have a basic knowledge in EE, the schematic posted in Naudin's site http://jnaudin.free.fr/kapagen/k32.gif  , the capacitor functions as a current limiter to the HV side.
The SG functions only during the second cycle, that the diode blocks the current.

a)The first cycle of current that charges the capacitor is not working accross the SG and the circuit consequently but across diode

CHANGE: I was wrong about energy lost. The cap acts as a voltage DOUBLER during the second cycle.

b)The second cycle of current that is blocked by diode and is commutated across the SG and working circuit. (MOT voltage + CAP voltage)

Calculations
................

Assuming the MOT is outputing 2100 volt at its high side, this means 2100* 2square equals almost 3000 volts. (max)
An 1mf cap working on this side, allows:
1/1000000 * 3000 * 50Hz *(2 cycles) = 0.3 Amps to flow (max)

In energy terms, E = 1/2 * C*V square = 4.5 J (max) * 50Hz *(2 cycles) = 900 watts (max figures)
In reality the above figures are not the ones anyone will observe but lesser ones.

...
But i think, nobody cares about what i say anyway. OU is the only wanted anyways   

[wings]

Seems to me it is rather an electrometer than a "telluric meter". Shouldn't be to check telluric currents at the ground between two points?

Telluric current is just one face of the ionosphere current.
see
Tesla emitter & Atmospheric Energy

energy is important but take care we live on this planet :
http://www.leyman.demon.co.uk/14%20Unhealthy%20Earth%20Energies,%20The%20Hartmann%20Net%20and%20Curry%20Gri.html