Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[verpies]

Yes, Energia9.  The power of the waveform at the output of the flyback driver constitutes the forced flow of energy into the device.
However this power cannot be measured by a multimeter that measures the average or RMS current and voltage, and certainly not at another point in the supply circuitry than the input of the Device Under Test (DUT).
Power can be accurately measured by a fast two channel multiplying oscilloscope or calorimetric/incandescent methods at the output of the flyback driver (input of the DUT)

That is not what you did, Wesley
You did not measure the power at the output of the flyback driver (nor at the input of the DUT).
In your video I saw you (plural) measuring the average input current (150mA AC) and average voltage (218V AC) at the input to the power-supply that powers your flyback driver.  Multiplying these average values does not even yield power. 

You could not even measure the current at the input of the DUT because your ammeter is rated at maximum of 1.5kHz and the output waveform from the flyback driver (input of the DUT) has the 16.8kHz frequency and it has harmonics even higher than that because it is not a clean sine wave.

The output power of the DUT was measured much better than input power (with the light bulb) and I would put much more faith into it. Unfortunately the brightness of the bulb was not measured by an isolated monotonic light sensor (eg. photodiode), so it is not scientifically credible either.

I am not a subjectively biased skeptic. I am an objective scientist.
I have never made Ad Hominem remarks to you nor engaged in conjecture about your devices.
I never stated that your device is not OU but I did write that your input power measuiring methodology is invalid, and scientific conclusions cannot be drawn from it. 
I still think so.

You are not helping yourself or the dissemination of this technology by ignoring these objections.
As a scientist you should value constructive criticism.

power usage of function gen can be xxWatt  but what is most important is how much power the signal is carrying

That is what we  did .

Look at my past comment few days ago,and look at  videos .
I can not respond to every skeptic individually. No time for it.

[Neo1]

Hi, I am sure this questions has been asked - however I have not seen a clear answer.

Signal Gernerator 1 supplies 50Hz @ 10 Volt to the 15 turn coil.

Typically the output impedance for a signal generator will be either 600 ohms or 50 ohms.

Either way a 15 turn coil is going to have an impedance of less than 1 ohm.

Wouldn't this effectively short circuit the signal generator output?

Please explain how the 50Hz signal is matched to the 15 turn coil?

Many thanks

[stivep]

You are not helping yourself or the dissemination of this technology by ignoring my objections.

Sir with all do respect you did not read  what I have asked you to do.


So I have suggestion.
After my video is loaded ( the one with corrections) like an hour from  now. Watch that video carefully.





"One  skilled in art and at his/her own responsibility  for this act might check it out."
The reason I use it in this form of expression is  obvious.

So  you have the answer  ready in front of you...instead of  just writing on this forum.


Simple?
Yes?
NO?
Maybe?




We do not need  to beat the bushes. got the message?


All  of my  past legal warnings about safety  including  full text of it , are in motion and must be applied.




Wesley

[nightwind]

Simple Power Measurement

Just show it as a self-runner.  We can worry later how about the COP variance.  I bet Verpies would even go for that.

[verpies]

Signal Gernerator 1 supplies 50Hz @ 10 Volt to the 15 turn coil.
Typically the output impedance for a signal generator will be either 600 ohms or 50 ohms.

Not necessarily. See:
http://www.youtube.com/watch?v=CJQt1mD7bIc

Either way a 15 turn coil is going to have an impedance of less than 1 ohm.

Yes, at 50Hz the impedance of the 15t coil would be less than 1ohm.
At 500kHz the same coil can have impedance of much more than 100ohms.

Wouldn't this effectively short circuit the signal generator output?

Yes, and it does for everyone who tried replicating this device except the STAAAR team.

Please explain how the 50Hz signal is matched to the 15 turn coil?

15 turns wound over a Metglas core which has a relative permeability of apx. 1000000, would offer significant inductance and much higher impedance than 1ohm.

...but the old russian ferrite has permeability thousand times less than Metglas.

Perhaps the effective permeablity of the ferrite is artificially increased by the rotating magnetic field and electric field pulses parallel to the axis of rotation.  There are known exotic effects of magnetic permeability modulation by electric fields. 
See the IEEE article I cited a while ago:

Such unconventional influence of the E field pulse on ferrimagnetic materials, even causing a variation in magnetic permeability, has been documented by Konrad and Brudny in an article titled "An Improved Method for Virtual Air Gap Length Computation" in IEEE Transactions on Magnetics, Vol. 41, No. 10 from October 2005.
The above effect was very dependent on the composition of the ferrite!