Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[xenomorphlabs]

And adding a lot of capacitors would be no mistake too.

The grounding question is this: DC needs a closed circuit to work. This is logical because the electrons in the wire are all moving in a circle due to a potential difference. Now why should AC also need a closed circuit to work? The electrons come from nowhere and they go to nowhere they are only vibrating in the wire.  But what can cause a strong vibration? Resonance, I think.

Kapanadze 28th April 2004 full version free energy device

At 24:33 Kapanadze pulls the plug, hence the inverter which provides the 50Hz frequency is cut off from the device instantaneously. Nevertheless the current flows through the lamps for another second. Question: What kind of current flows in that second through the lamps? AC or DC? I don't think it is DC since it was AC before the cut off. If the current is AC then at what frequency? 50Hz? From where? From the device (transformer) itself that is in a state of resonance for one more second without input?

An RLC circuit will continue to swap energy between L and C even after the source is disconnected until the stored energy is dissipated.

http://en.wikipedia.org/wiki/RLC_circuit -> Ï,, = 2∏ f √(L x C)
http://en.wikipedia.org/wiki/RC_time_constant -> Ï,, = R x C

[semenihin-77]

I am looking for brains, to work on the scheme 

delamorto@mail.ru

http://www.youtube.com/watch?v=mFn4nMRZoEg

[bass]

@all

@Peterae at overunityresearch dot com asked for some load specs so here is a small youtube showing these as well.

http://youtu.be/1CWWHKs3mzs

I hope some of you realize what this means relative to TK devices. Can it be so simple?

Tomorrow I will be adding a battery and an inverter and see how to loop it back. hehehe

Off to jam with friends "all night long". lolololololol

wattsup

Nice work. I would say that there is a way of theft of electricity, when the load, as in your experiment, one wire is connected to the phase and the other to ground (usually the water system as in a presentation of Kapanadze green box) Maybe this is the right way

This is something that anyone can check right now.

Do you want to experiment with this scheme?

[FreeEnergyInfo]

SCEMATIC ...

www.realstrannik.ru/forum/44-freeenergylt/87845-poisk-se.html?limit=18&start=17262#88028

[jbignes5]

Yes, exactly.
A mechanical DC ammeter is an averaging meter, and the average of a sine wave is zero.
At 50Hz the inertia of its needle does not allow it to move.

Go back to school Jbignes5 !!!
I am so sick of your illogic and loose mind.

No you must forget what your school has taught you. You mean to tell me that an analogue meter is an averaging meter? So if there is a diode in there then whats the average of all positive pulses? Duh.. The one that needs to get back to the basics is you.. 3 posts and you are sick of my illogical observations? Please...


"DC Amp meter

A  amp meter is a simple amp meter. Direct current is measured through a resistor or shunt placed in line with the circuit. The voltage is measured across the shunt.

  AC Amp Meter

An AC amp meter is used in two ways. One AC amp meter uses a system similar to a DC amp meter. The only difference is that an AC amp meter uses a bridge diode instead of a regular shunt as a resistor to measure current. The bridge diode changes negative into positive current to facilitate calibration and measurement. This is called the direct AC amp meter. The other type of AC amp meter works by emitting an electromagnetic field. A coil around the wire will pick up the field and run it through a resistor or shunt and measure the voltage of the electric current. The voltage drives a needle to help read the measurements of the current. This is called an indirect amp meter. Some AC amp meters are moving iron type amp meters. The magnetic field is attracted by a piece of metal mounted at one end of a needle. This type of moving iron amp meter can work also with DC."

Plus: if you actually read my post you will find that I said that 300k cycles is probably to fast for the analogue DC meter. But then again you don't pay attention. Reading is a virtue, Understanding is priceless.

Second Plus: if you can get a real current to flow through a capacitor then you are a marvel to behold.

I would have to look again at the video and see what that am meter uses as a shunt. If it is a diode which I believe it is then it would rectify half of the signal. The reason they use diodes is to make sure the needle doesn't swing in the other direction damaging the needle. But most meters use resistors so it remains to be seen. Again I have to reiterate that I will be using the correct meter unlike my example video.

If that is illogical then YOU need to go back to school.