Thane Heins BI-TOROID TRANSFORMER

[SchubertReijiMaigo]

I have one thing to say: Thane you are a genius !!! This my comprehension of your device to: In a voracious conventional transfomer the power factor is coupled Forward and Back, so if you have a PF of 0.5 at secondary you have to a PF a 0.5 at the primary. In full load if you a PF of 1 you have a primlary PF of 1... yes this crap burn your precious money

Now in the BITT case have a "divine" arrangement with three coils one primary and two secondary. Two magnetic path also, one smaller and one bigger. Here you have a magnetic diode that allow EMF to flow of the primary to secondary (in a symetrical way when using a very small air gap between core1 and core2). The BEFM flux is not allowed to return disrupting the primary but feed her sister... The two secondary is "twin sisters" they work together if you don't load one secondary the BTT cannot work correctly... So the primary is here to sustain the voltage, with the same numbers of turn half the voltage is feeded in one secondary so you need to connect them in series to have the full voltage of the primary (this case is true when the two secondaries are symetric). The BTT is a device with a great potential because you can explain this effect with conventional science and not "exotic" theory. In a certain case law of conservation are false, REACTIVE POWER CAN BE CONVERTED TO REAL POWER...

"Just as it ought to be in an LOVE based infinite universe!"
Unfortunately humans have a certain "fear" of infinty and immortality. Those concepts is very disrupting for some people...

[teslaalset]

IF THE POWER FACTOR IS 0 THERE IS NO POWER "CONSUMED" PERIOD, BECAUSE THE METER READS THE NET POWER BY MEASURING THE INPUT CURRENT FROM THE SOURCE ON ONE CYCLE vs THE OUTPUT CURRENT BACK TO THE SOURCE ON THE OTHER CYCLE.

THE "$ COST" ACCORDING TO THE METER IS HOW MUCH CURRENT IS RETURNED TO THE SOURCE.
AND THE CONSUMER PAYS THE DIFFERENCE.

THE BITT USES PURE REACTIVE CURRENT/POWER  (PF = 0) BUT DELIVERS REAL POWER TO THE LOAD(S).
SO THE NET METERED COST IS $0.00 BECAUSE THE INPUT FROM THE SOURCE ON ONE CYCLE (1/2 SINE WAVE) EQUALS THE OUTPUT RETURNED BACK TO THE SOURCE ON THE OTHER CYCLE ( OTHER 1/2 SINE WAVE).   

Indeed that is a clearer explanation.
Below you can see the differences in graphical form.
The black lines represent the power consumption
- The inductive load has positive and negative power consumption, equally distributed, so the net power consumption is zero
- The pure resistive load has only positive power consumption ending up in your power bill.

[penno64]

Hi all,

Thane, you are a genius, a gentleman and a great guy!

How wonderful to see someone develop an idea and all others access to it.

I hope you are immeasureably rewarded for your outstanding success.


Kindest Regards, Penno

[SchubertReijiMaigo]

Sorry for the off topic, here I try to explain the utility of the air gap in a magnetic circuit: Linearity against frequency, temperature, and magnetisation H...
Permeability is calculated by: u=B/H
When a magnetic circuit is linear the slope of the permability is constant.
When "       "           "     " not linear the slope of the increase rapidly, have a peak and decrease brutaly, in the BTT the non linearity of magnetic material is an ennemy, you must have stable and reliable permeability against H (amperage flowing in the coils) because reluctance is also closely linked with permeability (see page 3 of this topic)...

[teslaalset]

Sorry for the off topic, here I try to explain the utility of the air gap in a magnetic circuit: Linearity against frequency, temperature, and magnetisation H...
Permeability is calculated by: u=B/H
When a magnetic circuit is linear the slope of the permability is constant.
When "       "           "     " not linear the slope of the increase rapidly, have a peak and decrease brutaly, in the BTT the non linearity of magnetic material is an ennemy, you must have stable and reliable permeability against H (amperage flowing in the coils) because reluctance is also closely linked with permeability (see page 3 of this topic)...

SchubertReijiMaigo,

Why do you want to use a gaped core in BITT?

Saturation in the primary core is desired not to be avoided.
If the primary core is not saturated, part of the flux generated in the secondary core will be flowing to the primary core, introducing real power consumption.