New invention of motion less generation of electric power

[jan.kolar]

Added equation for Joule energy

[jan.kolar]

Hi Jan,
how would you do this ?

Just using one one wire (one connector pole) only ?

Wouldn´t this only work with high voltage ?

Sorry i have not answered this question clearly in my previous posts. My guess is, that Ali charges first capacitor with positive-halfwave and second capacitor with negative half-wave. So both capacitors should have slightly differing potentials and maybe charges. Third capacitor serves like free-energy collector i mean.

[hartiberlin]

Here is a better resolution diagram from Dr. Jeong, that he emailed me.
Enjoy !

Regards, Stefan.

[jan.kolar]

Additional notes to how Ali's circuit might be functioning.
If you charge first capacitor with positive half-wave and second capacitor with negative half-wave  (both with the same capacitance), this can be compared to two identical bath tubes, one above the other. Voltage accross capacitors (i.e. water level in our analogy) is the same, but first capacitor has higher potential energy (first bath tub is in higher elevation so has higher gravitational potential energy).
One more note regarding DSP & complicated software that Ali is using. I think another reason (beside what i mentioned) for such a solution is to optimize the process of capacitor charging. If you have simple serial RC circuit and connect it to constant DC voltage source then energy dissipated in resistance in process of charging is the same as energy of electric field in capacitor 1/2CU^2. Regardless of how large is R (1ohm, 10ohm, 100ohm,...)! You can compute this using Kirchhoff laws. I have made such calculations few years ago. To optimize the process of charging it is necessary to increase source voltage gradually. Some notes about this can you find on beginning of this article
http://www.physics.princeton.edu/~mcdonald/examples/EM/fundaun_ajp_60_1047_92.pdf

This technique is used in modern integrated circuits to save energy.

[Omega_0]

Hi folks

I am new at this forum. I have read all this thread and I am really curious if Ali's device is truly overunity or no. Sorry if my english is no perfect, I am from Slovakia.

I have some idea what this mysterious siphon effect could be. Imagine two capacitors with the same capacity C. Let both plates of both capacitors to be electrically neutral (i.e. number of positive and negative charges is the same). First capacitor is charged by moving some number of electrons from one plate to another. After that first plate has charge +Q and second plate has charge -Q. So the charge difference is 2Q. Voltage between plates then will be:
U1 = 2Q/C

Second capacitor will be initially charged by moving double amount of charges. So amount of charges at both plates will be -2Q and +2Q. Voltage between plates will be:
U2 = 4Q/C
Now comes important step. Imagine, that from some source we move charge -2Q to second plate. After this plate becomes electrically neutral. But first plate still contains charge -2Q, which creates potential difference:
U2' = 2Q/C (in absolute terms)

So if we use conventional voltmeter, these two capacitors will be indistinguishable. But if we connect positive pole of first capacitor with positive pole of second capacitor and negative pole of first capacitor with negative pole of second capacitor, there will be current flowing because of charge imbalances. So maybe not only voltage is important, but also potential! Remember, that Ali said, that his circuit must be powered with AC source with both polarities against neutral wire.

I'm sorry but its wrong. You could have tested it before posting.
You can't charge only one plate of a capacitor, the charge immediately appears on the other plate through induction.

The plate won't become electrically neutral, the second plate will immediately induce opposite charge in it, and the voltage will change. That's what capacitors do and that's how they work.