Scalar Wave - Energy

[xee2]

@ Loner

Thanks for any real information you can supply about Tesla's experiment.

Wow. You have been doing many interesting things. A circuit that freezes a wire is way beyond my knowledge. But, I have posted several simple circuits that will light a fluorescent tube with one wire and I do understand and can explain that process should you have any questions.

[xee2]

What is the reaction of water on RF ? If I put a RF transmitter antenna  under water can I detect RF outside ?

Salt water is a conductor and will short the antenna if the antenna is not insulated. Pure water is and insulator and the antenna will work in it (but not very well).

[xee2]

@ Loner

Xee2, I would enjoy an understanding of the process.

The fluorescent tube lights because there are some gas molecules inside that get ionized. That means that some of the electrons are pulled off of the atoms so that they no longer have equal positive and negative charges in them. Remember, an atom has all of the positive charge in the nucleus and for each positive charge there is an electron orbiting the atom when it is in its normal state. But if an electron is pulled off, the atom then number of positive and negative charges is no longer equal and the atom has a net positive charge. Such atoms are called ions. It only takes a few volts to pull electrons off of atoms. Sparks are blue because the nitrogen atom emit blue light when they are ionized and sparks ionized the nitrogen to make ions before it jumps a gap. Oops, I am getting off topic. The ions in the fluoresce tube are pulled from one end to the other by the high voltages on the ends of the tube as they reverse (tube can also be driven by DC but to keep it simple lets use AC). The high voltages accelerate the ions to high speeds just like the electrons in a TV tube. These accelerated ions crash into other atoms and emir UV radiation (you will have to learn about that later). The UV radiation then excites the phosphor on the tube which then emits visible light. All of this you probably know, and if not can find using Google. So what do we need to get the tube to light. We need high voltage AC. It turns out that it usually takes at least 500 volts for the tube to light. Once lit a lower voltage will keep it lit. So if you apply 500 volt AC across the tube it will light. The frequency of the AC does not matter. Most of my circuit use AC in the tens of kilohertz.The AC does not have to be a sine wave, pulses will work, even pulsed DC or plain DC will work (but it is a little harder to explain why and I am trying to keep it simple).

Does this make sense so far? You probably already knew all of this but it seemed like a good place to start.

[sparks]

  Below is my experiment.  The 1/4 wavelength of the cb output  is about 9 feet.  The antennae is copper magnet wire.
The coax was stripped and the inductance of the coax extended by the magnet wire.  The shield was just lying around.
Bulb will not light without glass of water.  Higher frequency photons contain all the lower frequency photons and are therefore able to be converted into visible light by photon scattering.  The atomic preference to absorb different photon types allows seperation of photons from a higher frequency (larger photon pack) and invisiblity to the unwanted photons in the pack.  In other words say you are transmitting 10 khz and your matter likes 6khz electron jumping.  4khz will be invisible to the matter and is passed on until it finally reaches a form of matter that likes 4khz jumping.  This second form of matter will then scatter 4kz photons.  The fluorescent coatings in a bulb cause visible light photons to be scattered while the lower frequency photons  just keep on trucking at the original velocity and phase of propogation.  Least that is what I understand about photon scattering and traveling waves and crossovers bandpass torroidal filter chokes etc.

[xee2]

@ sparks

  Below is my experiment. 

Is this something you actually did?