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Overunity Machines Forum



DIODES! Newman does not use his "special commutator" anymore

Started by kmarinas86, November 09, 2009, 04:19:12 PM

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kmarinas86

Diodes are used to separate the current surge of the back-spike away from the coil. This is essentially a current divider, and it is NOT a voltage divider. As a result, for a given current resulting from the back-spike, most of the power goes through the diodes, but the same voltage passes through both the diode pack and the circuit it connects across. The power of the back-spike comes from the energy of charges that got trapped at the end of a circuit whenever the gap was created. It is therefore depleted from that storage of energy. That is NOT overunity.

Since the energy of the back-spike is divided across the circuits, there is less of that spike's energy in the coil relative to the voltage it applies to it. Because voltage is electrical potential energy per charge, the amount of charge that corresponds to that applied voltage is reduced. This reduces the amount of energy dissipated by the collected charge which goes into the coil, allowing the atoms to align more effectively.

Quote from: kmarinas86 on August 29, 2009, 10:56:46 AM
It is clear from the operation of capacitors that a displacement current creates a magnetic field with the same polarity as current going the same direction.

When displacement current forms, a curl of the B-field is generated to which the magnetic moments of copper (a diamagnetic material) attempts to cancels out. Because such a B-field can be made of such a magnitude to domineer over the magnetic dipole moments among neighboring copper atoms, the subatomic particles of those copper atoms will attempt to align their magnetic moment dipole axes in helical configurations in contrast to their typical random configurations. The change of configuration actually consumes potential energy by the formation of "paratoroidic (magnetic) moments" of copper (an as-yet-unconfirmed paramagnetic analogue of the experimentally validated "ferrotordic (magnetic) moment").

See timeline on verification of ferrotorodicity: http://www.google.com/search?hl=en&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=Hek&tbo=1&tbs=tl%3A1&q=ferrotoroidicity&aq=f&oq=&aqi=

By keeping the impedance of the back-spike larger (i.e. voltage higher and its current lower) than in the initial pulse, copper's reaction to the voltage back-spike can provide the same polarity of magnetic field as current going forwards. The back-voltage does dissipate after a while, and you are right when you say that, "This oscillation seems related to the length of the conductor and maybe other factors like self-inductance, self capacitance, insulation, wire diameter, etc."

So where does the energy come from to restore the potential energy lost via alignment of the paratoroidic (magnetic) moments? Certain frequencies of electromagnetic radiation get absorbed by the (PARAtoroidic) arrangements of magnetic moments in the copper atoms, in effect, restoring their potential energy. When some of the moments fall out of alignment, others will follow suit.

I do not see this a violation of any laws of thermodynamics. The 2nd law in particular says nothing about any "impossibility" of zones of decreasing entropy, nor is it disproven by the existence of self-organizing structures. Don't get me started on the 1st law, that is simply fact because we can always define a potential energy in reference to new energies discovered. And the 3rd law is about absolute zero....

The generation of frost in some failed operations of the Steven Mark TPU device can be explained by generation of excess magnetic fields. If you remember the fact that temperature is dependent on motion, it is clear that atoms locked in position as a result of mutual magnetic inductance have a lower temperature; this is obviously not the same as keeping a macroscopic object still! At some point, this temperature change can spur surrounding photons to make up the difference, restoring the atoms into their natural, random configuration.

jadaro2600

Very interesting, but what does this have to do with Newman?

kmarinas86

Quote from: jadaro2600 on November 09, 2009, 05:07:41 PM
Very interesting, but what does this have to do with Newman?

He uses diodes in his device. He uses that to capture the current of the back-emf. This is done to prevent the coils from burning at higher-voltage switching. The voltage of the back-spike is still applied to the coil. That voltage aligns the atoms. The second half of the first post in this thread shows how that voltage aligns the atoms of that coil.

In the video below, you can see a demonstration made by Joseph Newman. At some portions of the video, he claims that he captured the back-spike and that he had built his own diode pack to achieve it.

http://video.google.com/videoplay?docid=-6157958993884349118&ei=EbD4SuONOZ3KqQKSldGTCg&q=joseph+newman+site%3Avideo.google.com&view=2&dur=3#

kmarinas86

When I connected the diodes in parallel, I was surprised by the fact that that their resistance did not reduce to the degree I had expected. There are two possibilities for this:

1) The tips of the diodes were not connected to allow for current movement.
2) Some other, yet unknown, reason.

This reduced the degree by which the current was able to diverge into the diode pack. I did not experience significant changes in rpm. I got my hopes up for a while though, then realized that this was simply due to me altering the commutator. There was no drop in back-spikes that couldn't be explained by the commutator.

In one part of Newman's video he talks a little about using diodes to capture the back emf:

http://video.google.com/videoplay?docid=-6157958993884349118

He does not make it clear as to whether it is connected with positive bias or negative bias. So it is possible that he inserts it using positive bias.

My plan now is to attach ONE diode forward-biased at the front the coil. The resistance of the diode will prevent forward current going to high. It will also block the flyback current from reaching the battery. However, it will cause charge to collect on the end-side of the diode, just like a capacitor. This will slow down charges going backward while not inhibiting charges going forward. This helps to maintain the forward current as well as the magnetic field. At the same time, any attempt to collapse the magnetic field would have to send the energy forward rather than backwards. However, to reach a magnetic field of zero, the charges would have to obtain zero velocity. This puts pressure on the electrons which increases their voltage. When the counter-emf no longer exists, the energy recovered by the electrons is dispensed at a smaller interval, and the process repeats itself.

The key is that with this process, electrons in the coil lose more energy in a given cycle then the would otherwise have been. This increases the potential difference between the electrons in the battery and those within coil, and this maintains the voltage of the battery better. This means more speed for the motor.

kmarinas86

It seems I keep on changing my hypotheses!

:P

Now I know that the diodes I am using do barely anything to change the operation of the system.

Also, know I am discovering that the commutator itself is of far greater importance. I am using smoother aluminum contacts this time.

When I have the motor operating at 120 rpm, I notice that the temperature of the wind tends to vary rapidly. Even when the thrust of the wind does not change, I can feel the temperature of the wind drop when meter shows negative spikes. Many of these negative spikes show up as negative 300 milliamps on the meter. Yet I am using 230 volts on 930 ohms. The downside is that the spikes can half as easily jump to postive 300 milliamps. The difference of temperature is unmistakable. I believe I am reaching the point where I am actually physically observing (feeling) a temperature drop below ambient.