Window Motor Doubles Voltage At The Power Supply [Overunity ?]

[poynt99]

Hi John,

Yes it may present a load to your motor because whenever the voltage level tends to be higher on the + motor wire than the output of supply voltage, the series diode will block the supply voltage and the motor current will load the diode bridge's output,  a situation a snake wishes to byte its own tail... 

rgds, Gyula

Good suggestion with the diode Gyula, however I'm not sure I agree with the above quote, or maybe don't understand what you are saying exactly.

There should be no load on the motor even if its output voltage at the bridge is higher than 20V.

.99

[gyulasun]

@.99

On load I mean the window motor's own current consumption, taken normally from the 21V supply, about a few hundred microamper as John said earlier.
No mechanical load on the shaft of the motor.

And in case the output voltage feedback from the bridge output to the positive supply wire of the motor is on and if this tends to increase the supply voltage above the 21V, then the diode blocks this extra voltage getting back into the power supply circuits and the motor will try to run faster. However this faster run surely increases its own current consumption so this fact will normally involve the reducement of the output voltage from the diode bridge because the source (in this case the diode output) gets its juice from the same "wire" it feeds. 
Normally for such feedback to work safely in case of any overunity I would normally use a decent DC-DC converter that has ground independent in/out terminals and that has a stabilised output voltage. Such converters has +90% efficiency so a circuit with a COP of 1.1 or say 1.2 couls surely be looped back by such converter.

Maybe I answered your question. 

rgds, Gyula

[DadHav]

Guys. I have another idea that I can't try until I get home again but: If the effect I'm seeing is completely dependent on the impedance matching between the supply and the motor coils, would it be possible to put 2 LAB batteries in series with the power supply, leaving the power supply set at zero volts. Is it possible the circuit would run and charge the filters in the power supply? Is it possible the impedance would stay the same with the power supply unplugged? If this should happen to work it would prove that a substitute input circuit could be made to support the anomaly shown in the video but this time using a battery that might except a charge from the setup. Full of prunes again right?
John

[lumen]

I think these regulated power supplies are not designed to directly operate inductive motor devices.
The timing is interfering with the power supplies regulator circuit and causing the supply to increase the output.
If this is not the case then the power supply would still continue to supply only the 20v and the motor would actually be supplying it's own power at 40v.

Just decouple the power supply with a large capacitor connected to the power supply and feed the motor through a diode.
This would allow the power supply to see only the voltage on the capacitor and would then show only the actual 20v supply.
If the motor was operating as it's own supply, then this should still occur and it would still accelerate up and produce 40v.

[DadHav]

Lumen. When you put it that way it does certainly sound to good to be true. Maybe I don't understand what you recommend. I can put a large cap on the output of the PS but once I add the diode it's likely the power supply wouldn't go up capacitor or not right? Maybe I don't picture what you say.
John