STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[Omnibus]

Not to mention E is not over R but over R and L, so of course it can't be used to calculate power through resistance  . But at this point he's at the level of a troll so no need for an educated correction.

@LarryC's behavior is pathetic. Really.

[LarryC]

Not to mention E is not over R but over R and L, so of course it can't be used to calculate power through resistance  . But at this point he's at the level of a troll so no need for an educated correction.

Finally, one of you tries to talk about the science, along with your child like name calling.

I used R because you two refused to believe in inductance. It is not R and L. It is Z (impedance), which is equal to the square root of (R^2 + X^2), where X is the inductive reactance.

Edit: Z is only slightly larger than R because of the low inductance of the air coil and would only slightly decrease Pin.

I have shown nothing but facts and can show the literature to prove it. 

Others will not believe you, if all you do is try to dismiss my evidence without proof.

Omni said I don't understand physics and reason. So here's your chance to teach us all.

Regards, Lary 

[Omnibus]

Finally, one of you tries to talk about the science, along with your child like name calling.

I used R because you two refused to believe in inductance. It is not R and L. It is Z (impedance), which is equal to the square root of (R^2 + X^2), where X is the inductive reactance.

Z is larger than R and would increase the Pin.

I have shown nothing but facts and can show the literature to prove it. 

Others will not believe you, if all you do is try to dismiss my evidence without proof.

Omni said I don't understand physics and reason. So here's your chance to teach us all.

Regards, Lary

Read carefully what I wrote, try to understand it. Try to understand what others wrote, including regarding reactance and R and then come back to discuss these issues. You are unprepared but are arrogantly pushing your confusion. Like I said, don't clog this discussion further with your gibberish.

[LarryC]

Read carefully what I wrote, try to understand it. Try to understand what others wrote, including regarding reactance and R and then come back to discuss these issues. You are unprepared but are arrogantly pushing your confusion. Like I said, don't clog this discussion further with your gibberish.

I can only assume that you think this is your proof:

'Of course P = E^2/R should not be used in this case because it isn't only Ohm's law that holds in this situation.'


I showed the following in my post:
'I used R because you two refused to believe in inductance. It is not R and L. It is Z (impedance), which is equal to the square root of (R^2 + X^2), where X is the inductive reactance.

Edit: Z is only slightly larger than R because of the low inductance of the air coil and would only slightly decrease Pin.'

I am the other that wrote about reactance, so you want me to read my own post.

I'll be glad to calculate Z if you give the inductance of your air coil. I have similar air coil, which I can take the inductance if you can't.

Regards, Larry

[Omnibus]

I can only assume that you think this is your proof:

'Of course P = E^2/R should not be used in this case because it isn't only Ohm's law that holds in this situation.'


I showed the following in my post:
'I used R because you two refused to believe in inductance. It is not R and L. It is Z (impedance), which is equal to the square root of (R^2 + X^2), where X is the inductive reactance.

Edit: Z is only slightly larger than R because of the low inductance of the air coil and would only slightly decrease Pin.'

I am the other that wrote about reactance, so you want me to read my own post.

I'll be glad to calculate Z if you give the inductance of your air coil. I have similar air coil, which I can take the inductance if you can't.

Regards, Larry

This is gibberish and is to be ignored.