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Overunity Machines Forum



STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

Started by PaulLowrance, December 04, 2009, 09:13:07 AM

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teslaalset

Quote from: teslaalset on July 01, 2010, 08:30:19 AM
@Omnibus
I had a very close look at your Excel and found 3 possible corrections:
- You applied 3.14159 for pi. If you use 'pi()' instead, your accuracy will increase
- in column E you made a typo. 16.5 should be 15.6, as you used 15.6 volts
- in column I you used 100 ohms. this should be 10 ohms

Attached the corrected result. Do you agree?

I forgot to mention a 4th correction:
The timescale per degree is not correct. Per degree it should be 1/(800000*360)
This is also corrected in the new file I attached earlier

teslaalset

Quote from: broli on July 01, 2010, 07:48:16 AM
I need to crawl back in my cave for a while as things are getting fuzzy. For me the average of power ie energy dissipation per second is a very straightforward quantity. Calculating energy and then getting the slope is for me an unnecessary work around in a continuous system. I have to think about the points you and teslaalset raised. So I'll use some time to think about it until you can share your experimental data.

Take it easy, Broli.
We do this for fun  ;)

Omnibus

Quote from: teslaalset on July 01, 2010, 08:30:19 AM
@Omnibus
I had a very close look at your Excel and found 3 possible corrections:
- You applied 3.14159 for pi. If you use 'pi()' instead, your accuracy will increase
- in column E you made a typo. 16.5 should be 15.6, as you used 15.6 volts
- in column I you used 100 ohms. this should be 10 ohms

Attached the corrected result. Do you agree?

I agree but check these out. I'm back to 700kHz and 100pF. Hope I've made less errors this time.

Of course, I have to answer my own point now regarding the comparison of energies at the end of a period -- as seen, even when the in-slope is negative the quotient of the energy out over energy in is less than 1.

Omnibus

Quote from: teslaalset on July 01, 2010, 09:45:36 AM
Take it easy, Broli.
We do this for fun  ;)

I second that. We have to do this in a more leisurely way. No pressure no nothing. Take it easy, indeed.

broli

I have attached the mathematical equation for the energy equation. Basically it's the indefinite integral of the integrals I have been using. When you plot these equations you get the energy plots you guys have been sharing but without needing discrete data points. When you use them be careful to get everything right as it's easy to make a slip of the pen and throw everything off.

The C's at the end are integration constants. They need an initial condition at t = 0 for instance to fill out.