Mostly Permanent Magnet Motor with minimal Input Power

[gotoluc]

Yep! Except that if "by second" it means you ask for Watts and not Joules ^_^ but I will give you both:


● For 1 mm height:

W [J] = 2.35 [kg] × ~10 [m.s^-2] × 1/1000 [m]

= 23.5/1000 [kg.m^2.s^-2] = 0.0235 [J]


If not clear enough, please just tell me

Okay, question

if I raise 2.35Kg up 1mm with 0.0245 Joule, are you saying the time it takes for the weight to rise or the time it stays up 1mm is not important?

Luc

[Khwartz]

Exactly,  if about "potential energy", the duration of the lifting doesn't matter, indeed. BUT if it was about "power" (Watts) it would be.

Nevertheless, it is not always completely true in practice: if we ask an electric motor to lift very fast a weight it will have non-proportional loses and the energy consumed will be a little bit more. But we are talking about energy CONSUMPTION

But for your simple lifting experiments I don't think it is relevant to care care if only electromagnets.

IMPORTANT NOTE:

The calculation W = M.g.h gives the change of potential energy in the gravitational field. It means that when the mass is on the floor its "gravitational potential energy" respect to the floor is zero, and when lift of any height it may restitue some energy when falling. This is this "potential falling energy" we have calculated.

[gotoluc]

I received a PM from poynt99 but he has blocked me to reply.
I know he may not be happy with me sharing his message but I'm doing it so you can see and understand my reply to him.

Luc

Don't worry Luc,

I'll not "intrude" with my "words" any longer in any of your threads.

I'll have no difficulty putting that time to good use. 

Cheers!

Dear poynt99

what I wrote was not specific to you, so don't take it personally.

You have been of much help through the years and I would like to thank you for that.

You are well learned in EE but we both know to find what FE researchers are looking for we won't find it in the science books.

I know it must be painful for you to see us trying to reinvent the wheel but maybe that's what it takes?

Kind Regards and many thanks for all your help

Luc

[i_ron]

Ron, please do keep up your experiment and share your findings as it is worth more then words.


Luc

Always a pleasure to work with you Luc.


I have touched up your graphic to show that you are quite correct. Although what you show is a simplification the outcome is the same as my crude sketches. So across the top of the graphic we
have a South pole, North pole (centre) South pole.


I have added the major Bloch walls in yellow. I have indicated the poles on the outer sleeve as if it was metal. (I know this was not the case) This ties in with the original E core graphic on page one where on DC we would have a S, N, S, on the E core legs, utilizing the the outer field of the coil.


What my sketches show (I hope) is how we can have the core and the coil both having the same N pole.
Well simply put, the 'hidden' south pole is generating the North pole.


So you are right on with your original graphic Luc, good work as always!!!


Ron

[i_ron]

Here we have the sensor in the orientation that I suggested earlier.

Notice how the lines of force with the sensor in the middle, the sensor should read more than to the left or right, sorta opposite of the way you measured it in the vid. Not that you did anything wrong. Im just giving a view of looking at the fields in a second dimension to show a more complete view of the fields. A third dimension of the field would be to face the sensor with the length of the wire/leg of the coil.

Mags

Thanks for all your work with the graphics, yes I see what you are saying. I wondered at the time if it was a sensor position artifact but eventually ruled this out. What I found  with a small diameter neo stack is that it would adhere to any face of the coil in a manner consistent with what the hall probe had indicated!


Anyway nobody has to accept my results without doing the experiment, it is easy enough. I gave a link to the 'easy gauss meter', any coil with a rectangular cross section will be the subject, any magnet stack can be a sensor. The one question to ask is "why does the North pole of the magnet stack stick to the North pole of the coil? (please refer to one of my sketches for orientation)... [or, why does the core become a North when adjacent to the coils North?]


Thanks, Ron