Mostly Permanent Magnet Motor with minimal Input Power

[Khwartz]

Take a well wrapped bifilar solenoid coil connected serially with a welding rod core. Hang a steel carving knife by a string. Aim the center of the coil at the dangling knife and pulse it like you would a Leedskalnin device shorting the coil across a 12 volt battery. Watch what happens to the knife. Next, move the coil further away and try it again. This laser dimension magnet wave was broadcasted and received by Tesla at a distance of 40 miles from his downtown laboratory to West Point on line of sight. This was the first wireless transmission in History!. The broadcast and receiver coils were identical and both were grounded. The wave carried power that Tesla believed traveled through the ground! 

I re-discovered this effect by accident as I've recounted in the past: My first shop wound bifilar coil, 350 turns of 22 gauge, with welding rod core slid around ten feet to collide with a cutlery box that was drawn an equal distance along my kitchen counter, from one direct short pulse. The experience was traumatic! The magnetic force produced this way had nothing whatsoever to do with the customary D.C. Joule to coil flux ratios. Try it!

Hi synchro1. Thanks for your input
I am not English tongue and have hard time to well understand your experiment,  may you publish a schematic of with the according values of the different characteristics?

[synchro1]

Hi synchro1. Thanks for your input
I am not English tongue and have hard time to well understand your experiment,  may you publish a schematic of with the according values of the different characteristics?

@Khwartz,
Check this lost and newly re-published "Telos" Quadra test:

http://www.electrogravity.com/TELOSTESTS/vectorpot1.htm

[gotoluc]

error post

[Khwartz]

Ignoring the false precision for the moment, energy E in Joules on a capacitor  is
E = 1/2 (CV²)

So your starting energy in Joules is
E = 1/2(650 F x 2.07197 V x 2.07197 V) = 1395.244396292 Joules.
Ending energy in Joules is
E = 1/2(650 F x 2.07110 V x 2.07110 V) = 1394.07294325 Joules.

You got the right answer even though your stated formula is wrong. Therefore you did not use your stated formula, but actually used the correct one.

It is really difficult to check your work if your answers and your formulae do not agree.

Can you really measure voltage on a capacitor to the tens of microvolts precision? I am jealous.

hehe, you're right, TK, Luc didn't put the formulas right but he got the right results cause he simplified in his optmised mind its expression

For the calculation of efficiency, I would like to bring your attention all that here, we are indeed working against gravity and that the complete maths must include the mechanical energy of the dropping to get the right COP:

Lifting energy consumption: 1.17 joules.

Electrical flyback energy recovered: 0.34 joules.

Dropping mechanical energy which may be harvest: 0.53 joules.

-> COP : (0.34 + 0.53) / 1.17 = 0.74.

[Khwartz]

Mmm-ok,so this is working much like the maglev train dose.\
Quote: So now you're observing a visual of this effect and why this cannot go to OU.
If only there was a way to have separate power source lead's.

Wait just a minute there-lets not give up yet,as i believe there is a way to fix this problem. You have done before what is needed here Luc,and now you must do it again.It's time to put the effects of two of your projects together. You need to offset the voltage and current by 180* during the P/in cycle to your coil,so your going to need a pulsed input at the right frequency for your setup. As you know,when you switch of an inductor,the current will keep flowing in the same direction,BUT the voltage polarity will reverse-->If only there was a way to have separate power source lead's.
You dont need seperate lead's,as one set will do both job's,but you have to get the offset and frequency right for that coil.Normally with an air core inductor(coil) you would need a high frequency,but with that strong magnetic field i think the frequency needed would be quite low.

First to nut out a circuit to do the job,then find the right frequency to offset the current and voltage.To do this you need to fully understand as to what happens when an inductors P/in is suddenly cut off when running with a 180* current/voltage offset in the strong magnetic field it is in.This is something i dont remember anyone here ever looking into,or try doing. But i have actually done this myself,although the setup was a little different. I believe i called that particular project the magneformer-not quite sure,as it was some time ago. I remember showing TK my result's at being able to get a 180* offset of current over voltage,and if i remember rightly,he said i was creating a standing wave within the unit.This way i was able to maintain a continuous current flow within the inductor,but charge a cap with an opposite potential than that of my P/in-useing the same two wires. The circuit wasnt all to different to that of the SSG,which basically dose the exact same thing if you look at how the circuit work's-the negative of the charge battery is hooked to the positive of the run battery.

I guess the thing you will need to make this work is a signal generator-do you have one of these?.

Very Great imput: Cery Relevant imho, Brad!

It makes me think of the way guys like Jim Murray and Paul Babcock set their devices so that the source of power "doesn't see it":

http://www.emediapress.com/go.php?offer=Khwartz&pid=19

It is too what looks to happen in the Richard Vialle's Autogenerator when he speaks about "negative power" going back to the power source through a king of "virtual resistor" in the theoretical model of former transistor he used when the electronic laboratory got apparently the OU:

http://www.overunity.com/12639/richard-vialles-new-theory-about-negative-mass-and-overunity/nowap/#.VEVRs3OvTqA